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Effectus [21]
2 years ago
13

At a local high school, enrollment in the drama club increases by 5% each year. what is the common ratio in this situation? 0.05

0.95 1.05 1.95
Mathematics
1 answer:
CaHeK987 [17]2 years ago
5 0

At a local high school, enrollment in the drama club increases by 5%. the common ratio will be 1.05.

<h3>What is the percentage?</h3>

A percentage is a minimum number or ratio that is measured by a fraction of 100.

At a local high school, enrollment in the drama club increases by 5%.

Let an initial number of students in high school be 'a'.

so next year increase in students will be = 5% of a

                                                                   = 5/100 × a

                                                                   = 0.05a

and total number of the students will be  = ( a + 0.05a )

                                                                   = ( 1.05a )

So common ratio of the geometric square formed

( 1.05a )/ a =  1.05

Therefore, the common ratio will be 1.05.

Learn more about percentages;

brainly.com/question/14816043

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The quantity demanded for a certain brand of portable CD players is 200 units when the unit price is set at $90. The quantity de
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Given that the quantity demanded for a certain brand of portable CD players is 200 units when the unit price is set at $90.

If we set quantity=y and price=x then in point form, we can write above information as (90,200)

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Now we can plug both points into two point formula to find the required equation:

\frac{y-y_1}{x-x_1}=\frac{y_2-y_1}{x_2-x_1}

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3 years ago
What is the y-intercept of the line shown below? Enter your answer as a coordinate pair.
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7 0
2 years ago
What at 25 equations that equal 36
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7 0
3 years ago
I really need help
telo118 [61]

Question 1:

(attached is a graph of the data)

The graph seems to show a negative trend. Each value is usually less than the value before it.

People may only want to see the first game and decide to not show up to any others. Or maybe, as more games occurred, the weather was colder and people didn't want to go out in the cold.

Question 2:

  • St John's    | 174000 | 173000
  • Sudbury     | 165000 | 155000
  • Saint John | 126000 | 123000
  • Chicoutimi | 160000 | 155000
  • Thun. bay  | 127000 | 122000
  • Regina       | 194000 | 193000
  • Trois-Riv.   | 140000 | 138000

(attached is a graph of the data)

I chose this graph type to demonstrate each city, as well as the change in population over time.

I notice that, for each city, the population decreased slightly from 1996 to 2001.

The graph shows the trend because the pink bar (2001) is lower than the orange bar (1996).

Predicting values for 2006:

  • St John's    | 172000
  • Sudbury     | 145000
  • Saint John | 120000
  • Chicoutimi | 150000
  • Thun. bay  | 117000
  • Regina       | 192000
  • Trois-Riv.   | 136000

To find these values, I found the difference from 1996 to 2001 (<em>for St John's: </em>174000-173000 = 1000). Since 1996 to 2001 is 5 years, and 2001 to 2006 is also 5 years, I can subtract 1000 from 2001's value (173000 - 1000 = 172000). Another example (for Saint John): 126000 - 123000 = 3000. 123000 - 3000 = 120000.

5 0
3 years ago
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