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2 years ago

What is 0.1 to 0.2 percent changes, to test your brain.

Mathematics

1 answer:

nadya68 [22]2 years ago

7 0

Answer:

100% increase

Step-by-step explanation:

0.1 to 0.2

0.1 = 100% (original number)

0.2 - 0.1 = 0.1

0.1 = 100%

You might be interested in

2 times a number is the same as 12 minus 3 times the number. What

Ksju [112]

Answer:

a. 2n = 3n − 12, 12

Step-by-step explanation:

Let the number be represented by n.

Then 2 times the number is 2*n = 2n

3 times the number = 3*n = 3n

12 minus 3 times the number is 3n-12

It is given that 2 times the number is the same as 12 minus 3 times the number.

Expressing this equation form:

$2n=3n-12$

Solving the equation,

$3n-2n=12$

$=> n=12$

Hence the required number is 12.

3 0

3 years ago

Read 2 more answers

borishaifa [10]

Answer:

add a picture reading this is too hard

Step-by-step explanation:

3 0

2 years ago

jem pastes 21 photos and 15 postcards in a scrap album. she puts 3 items on each page. how many pages does jem fill in the scrap

ddd [48]

12 pages

Each side count as a page

21+15=36 36/3=12

6 0

4 years ago

5 more than the product of 23 and a number n

denis-greek [22]

Answer:

23n +5

Step-by-step explanation:

break down the expression into parts

5 more is +5

product is multiplication of 23 and n so 23n

then put it together

please give thanks :)

3 0

3 years ago

Read 2 more answers

Find the indefinite integral by using the substitution x = 4 sec(θ). (Use C for the constant of integration.) x2 − 16 x d

guapka [62]

Answer:

$\frac{x^2-16}{2} + 16ln\frac{4}{x} +16C$

Step-by-step explanation:

Given the indefinite integral $\int\limits{\frac{x^2-16}{x} } \, dx$ , using the substitute

x = 4 sec(θ)...1

The integral can be calculated as thus;

First let us diffrentiate the substitute function with respect to θ

dx/dθ = 4secθtanθ

dx = 4secθtanθdθ... 2

Substituting equation 1 and 2 into the integral function we will have;

$\int\limits{\frac{(4sec \theta)^2-16}{4sec \theta} } \, 4sec \theta tan \theta d \theta\\\int\limits{\frac{16sec^2 \theta-16}{4sec \theta} } \, 4sec \theta tan \theta d \theta\\\int\limits{\frac{(16(sec^2 \theta-1)}{4sec \theta} } \, 4sec \theta tan \theta d \theta\\\\from \ trig \ identity,\ sec^2 \theta - 1 = tan^\theta\\\\\int\limits{\frac{16 tan^2 \theta}{4sec \theta} } \, 4sec \theta tan \theta d \theta\\\\\int\limits 16 tan^3 \theta d \theta\\\\$

Find the remaining solution in the attachment.

3 0

3 years ago