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liraira [26]
2 years ago
14

Paul and Art are going to start a business selling fresh vegetables in their neighborhood. They

Mathematics
1 answer:
bearhunter [10]2 years ago
5 0

The system of 5x + 2y ≤ 25 is given by 20x + 15y ≤ 120 and 5x + 2y ≤ 25

<h3>Equation</h3>

An equation is an expression used to show the relationship between two or more variables and numbers.

Let x represent the cucumber and y represent the amount of carrots, hence:

20x + 15y = 2(60)

20x + 15y ≤ 120  (1)

Also:

5x + 2y ≤ 25 (2)

The system of 5x + 2y ≤ 25 is given by 20x + 15y ≤ 120 and 5x + 2y ≤ 25

find out more on Equation at: brainly.com/question/2972832

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Ne4ueva [31]

Answer:

Step-by-step explanation:

Triangle ABC is a right angle triangle.

From the given right angle triangle

AB represents the hypotenuse of the right angle triangle.

With m∠A as the reference angle,

AC represents the adjacent side of the right angle triangle.

BC represents the opposite side of the right angle triangle.

To determine AB, we would apply the Cosine trigonometric ratio

Cos θ = opposite side/hypotenuse. Therefore,

Cos 52 = 10/AB

0.616 = 10/AB

AB = 10/0.616

AB = 16.23

6 0
3 years ago
Better Products, Inc., manufactures three products on two machines. In a typical week, 40 hours are available on each machine. T
Kaylis [27]

Answer:

z (max)  =  1250 $

x₁  = 25    x₂  =  0   x₃  =  25

Step-by-step explanation:

                                Profit $    mach. 1      mach. 2

Product 1     ( x₁ )       30             0.5              1

Product 2    ( x₂ )       50             2                  1

Product 3    ( x₃ )       20             0.75             0.5

Machinne 1 require  2 operators

Machine   2 require  1  operator

Amaximum of  100 hours of labor available

Then Objective Function:

z  =  30*x₁  +  50*x₂  +  20*x₃      to maximize

Constraints:

1.-Machine 1 hours available  40

In machine 1    L-H  we will need

0.5*x₁  +  2*x₂  + 0.75*x₃  ≤  40

2.-Machine 2   hours available  40

1*x₁  +  1*x₂   + 0.5*x₃   ≤  40

3.-Labor-hours available   100

Machine 1     2*( 0.5*x₁ +  2*x₂  +  0.75*x₃ )

Machine  2       x₁   +   x₂   +  0.5*x₃  

Total labor-hours   :  

2*x₁  +  5*x₂  +  2*x₃  ≤  100

4.- Production requirement:

x₁  ≤  0.5 *( x₁ +  x₂  +  x₃ )     or   0.5*x₁  -  0.5*x₂  -  0.5*x₃  ≤ 0

5.-Production requirement:

x₃  ≥  0,2 * ( x₁  +  x₂   +  x₃ )  or    -0.2*x₁  - 0.2*x₂ + 0.8*x₃   ≥  0

General constraints:

x₁  ≥   0       x₂    ≥   0       x₃     ≥   0           all integers

The model is:

z  =  30*x₁  +  50*x₂  +  20*x₃      to maximize

Subject to:

0.5*x₁  +  2*x₂  + 0.75*x₃  ≤  40

1*x₁  +  1*x₂   + 0.5*x₃       ≤  40

2*x₁  +  5*x₂  +  2*x₃        ≤  100

0.5*x₁  -  0.5*x₂  -  0.5*x₃  ≤ 0

-0.2*x₁  - 0.2*x₂ + 0.8*x₃   ≥  0

x₁  ≥   0       x₂    ≥   0       x₃     ≥   0           all integers

After 6 iterations with the help of the on-line solver AtomZmaths we find

z (max)  =  1250 $

x₁  = 25    x₂  =  0   x₃  =  25

6 0
3 years ago
TIME CRUCIAL!! i will give you thanks please help!!! ASAP! will mark as brainliest!!
ozzi
\overline{y} (prounounced "y bar") is the mean of the y values

Add up the y values to get
5+7+10+15+18 = 55

Then divide by 5 (because there are five y values) to get
55/5 = 11

Therefore,
\overline{y} = 11

The answer is choice C
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3 years ago
A guy-wire is attached to a pole for support. If the angle of elevation to the pole is 67° and the wire is attached to the groun
Andrews [41]
The angle = 67<span>° and the pole is a right-angled triangle. Therefore the distance required to find (say "x) is the angle opposite the right-angle. The following equation needs to be solved:

cos 67 = 137 / x

Solving for x;
x = 350.62 ft</span>
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3 years ago
How can you simplify <br><br> No viruses please
Alexeev081 [22]

Answer:

In order to simplify a fraction there must be:

A number that will divide evenly into both the numerator and denominator so it can be reduced, or

The numerator must be greater than the denominator, (an improper fraction), so it can be converted to a mixed number.

Step-by-step explanation:

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