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2 years ago

7

Plz tell me all five and i will give u a brainliest

1 answer:

Maru [420]2 years ago

5 0

Answer:

#1=C #2=sorry, i cant help you there #3=D #4=3/4 #5=2

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Need help on this please

alexandr402 [8]

Answer:

5.7

Step-by-step explanation:

7^2- 4^2= 33

$\sqrt{33}$ = 5.7

7 0

2 years ago

Read 2 more answers

On a coordinate plane, a curved line labeled f of x with a minimum value of (1.9, negative 5.7) and a maximum value of (0, 2), c

Bumek [7]

Answer:

4.F(x) > 0 over the intervals (-0.7, 0.76) and (0.76, ∞).

Step-by-step explanation:

6 0

2 years ago

If i won 10 games out of 16, how many games would i need to paly to win 50

MrRa [10]

Ratio is 10:16, so to win 50, its 50:190, so you need to play 190 games to win 50

7 0

3 years ago

Read 2 more answers

Q6: Which is the graph of the polar equation r=1/1-sin theta.

AveGali [126]

Answer:

The correct answer is C.

Step-by-step explanation:

The given equation is;

$r=\frac{1}{1-\sin(\theta)}$

This implies that;

$r(1-\sin(\theta)=1$

$r-r\sin(\theta)=1$

Let us write in Cartesian coordinates by substituting;

$r=\sqrt{x^2+y^2} ,y=r\sin(\theta)$

$\sqrt{x^2+y^2}-y=1$

$\sqrt{x^2+y^2}=y+1$

Square both sides;

$(\sqrt{x^2+y^2})^2=(y+1)^2$

This implies that;

$x^2+y^2=y^2+2y+1$

$x^2=2y+1$

$y=\frac{1}{2}x^2-\frac{1}{2}$

This is an equation of a parabola that opens upwards with a y-intercept of $-\frac{1}{2}$ .

The correct choice is C

4 0

3 years ago

At a certain time of the day, a tree that is x meters tall casts a shadow that is x-49 meters long. If the distance from the top

nikklg [1K]

The height of the tree is 60 meters.

Explanation:

Let the height of the tree be x. The tree casts a shadow of $x-49$ meters and the distance from the top of the tree to the end of the shadow is $x+1$ meters.

The sides of the triangle are attached in the image below:

Using pythagoras theorem,

$x^{2}+(x-49)^{2}=(x+1)^{2}$

Expanding, we get,

$2 x^{2}-98 x+2401=x^{2}+2 x+1$

$2 x^{2}-98 x+2400=x^{2}+2 x$

$2 x^{2}-100 x+2400=x^{2}$

$x^{2}-100 x+2400=0$

Solving the equation using the quadratic formula $x=\frac{-b \pm \sqrt{b^{2}-4 a c}}{2 a}$ , we get,

$x=\frac{-(-100)\pm\sqrt{(-100)^{2}-4 \cdot 1 \cdot 2400}}{2 \cdot 1}$

Simplifying, we have,

$x=\frac{100\pm\sqrt{10000-9600}}{2}$

$x=\frac{100\pm\sqrt{400}}{2}$

$x=\frac{100\pm{20}}{2}$

Thus,

$x=\frac{100+20}{2} \\x=\frac{120}{2} \\x=60$ and $x=\frac{100-20}{2} \\x=\frac{80}{2} \\x=40$

where the value $x=40$ is not possible because substituting the value $x=40$ in $x-49$ results in negative solution. Which is not possible.

Hence, the value of x is 60.

Thus, The height of the tree is 60 meters.

7 0

3 years ago