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Alex
1 year ago
11

Mr. Stevenson wants to purchase a new hat. The table below shows the prices of various hats. What is the difference, in dollars,

between the mean price and the median price of a hat from the list?

Mathematics
1 answer:
Anastaziya [24]1 year ago
4 0

Answer:

39 - 35 = $4

Step-by-step explanation:

mean: 19+42+35+40+39 = 175

            175/5 = 35

add up all the cost then divide by how many numbers there are.

Median:

list the numbers from lowest to largest

19, 35, 39, 40, 42

then find the number in middle

39

last: 39-35=$4

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The tallest tree in the United States is a
erastovalidia [21]
Redwood hope this helps
6 0
2 years ago
The fourth term of an Arithmetic Sequence is equal to 3 times the first term, and the seventh term exceeds twice the third term
11Alexandr11 [23.1K]

Answer:

The first term is 3. The common difference is 2.

Step-by-step explanation:

The first term is x.

The common difference is d.

The second term is x + d.

3rd term: x + 2d

4th term: x + 3d

7th term: x + 6d

"The fourth term of an Arithmetic Sequence is equal to 3 times the first term"

x + 3d = 3 * x       Eq. 1

"the seventh term exceeds twice the third term by 1"

x + 6d = 2(x + 2d) + 1       Eq. 2

Simplify Eq. 1:

2x = 3d

Simplify Eq. 2:

x + 6d = 2x + 4d + 1

x = 2d - 1

Multiply both sides of the last equation by 2.

2x = 4d - 2

2x = 3d   (simplified Eq. 1)

Since 2x = 2x, then the right sides are equal.

3d = 4d - 2

d = 2

2x = 3d

2x = 3(2)

2x = 6

x = 3

Answer: The first term is 3. The common difference is 2.

8 0
3 years ago
Is 4(4a+20b) equivalent to 16a+24b
8090 [49]
No.

When you are distributing, you are multiplying to each monomial

4(4a) = 16a

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To write the function to show the weekly growth rate of population , we first find the weekly growth rate by dividing yearly growth rate by 52 ( as there are 52 weeks in an year)

Given function is ,

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To convert in weekly growth rate , divide 0.016 by 52

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or

P=120(1+ \frac{1}{3250})^{52t}

And the weekly growth rate = \frac{1}{3250}

7 0
3 years ago
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