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HACTEHA [7]
3 years ago
7

Write two expressions that have a GCF of 8xy.

Mathematics
1 answer:
V125BC [204]3 years ago
8 0
8xy and 4xy are two possible answers.
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Samantha just opened a new restaurant. She earned $550 on the first day and $750 on the third day that she was open for business
mr Goodwill [35]

Answer:

Step-by-step explanation:

If Samantha's earnings continue to increase at the same rate, this means that her earning is increasing arithmetically.

If she earned $550 in the first day, we can say the first term is $550

If she earned $750 on the third day, we can say the third term is $750

For us to know by how much her money is increasing, we need to find the common difference d formed by the sequence

550, x , 750

T1 = 550

T2 = x

T3 = 750

Common difference d = T2-T1 = T3-T2

x - 550 = 750 - x = d

Let's calculate the second term first i.e x

Since x - 550 = 750 - x = d

x - 550 = 750 - x

Collect like terms

x+x = 750+550

2x = 1300

x = 1300/2

x = 650

d = T2-T1

d = x - T1

d = 650-550

d = 100

Hence her money keeps increasing by $100 each day

8 0
3 years ago
If x=4 canculate the value of x2 + 2x
alexandr402 [8]

If u check your answer on google ithink u can get

6 0
3 years ago
Read 2 more answers
What is the slope of the line passing through the points
Bingel [31]

Hello!

Answer:

\boxed{2}

Step-by-step explanation:

Slope=\frac{Y_2-Y_1}{X_2-X_1}=\frac{RISE}{RUN}

\frac{1-(-5)}{4-1}=\frac{6}{3}=2

Therefore, the slope is 2, which is our final answer.

Hope this helps!

Have a nice day! :)

:D

Thank you!

6 0
3 years ago
Y=1x+2 y=3x-4 use substtiution
postnew [5]

Answer:

3Y - 4X - 4

Step-by-step explanation:

7 0
3 years ago
Read 2 more answers
Find all the critical points of the function <img src="https://tex.z-dn.net/?f=%20f%28x%29%3D%20%28x%2B1%29%2F%28x-3%29%20" id="
yulyashka [42]

The function

... y = 1/x

has derivative

... y' = -1/x²

which has no zeros. It is undefined at x=0, the only critical point. The derivative is negative for all values of x, so the function is decreasing everywhere in its domain.

Your function

... y = (x+1)/(x-3)

can be written as

... y = 1 +4/(x-3)

which is a version of y = 1/x that has been vertically scaled by a factor of 4, then shifted 1 unit up and 3 units to the right. Shifting the function to the right means x=3 is excluded from the domain (and the interval on which the function is decreasing).

The critical point is x=3.

The function is decreasing on (-∞, 3) ∪ (3, ∞), increasing nowhere.

5 0
3 years ago
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