Question

What is the product of (2p 7)(3p2 4p – 3)? 6p3 29p2 – 34p 21 6p3 29p2 – 22p 21 6p3 29p2 22p – 21 6p3 29p2 34p – 21

Answer 1

The product of the two provided equations, obtained by multiplying each term of the first equation from the second one, is 6p³+29p²+22p-21.

What is the product of two equations?

To multiply the two equation, each term of the first equation is multiples from the second term.

• The first equation provided in the form of binomial as,

         $2p+ 7$

• The second equation provided in the form of quadratic equation as,

        $3p^2 +4p-3$

The product of these two equations are,

$P=(2p+7)\times (3p^2 +4p-3)\\P=6p^3+8p^2-6p+21p^2+28p-21$

Arrange the equation with the same power terms,

$P=6p^3+8p^2+21p^2-6p+28p-21\\P=6p^3+29p^2+22p-21$

Hence, the product of the two provided equations, obtained by multiplying each term of the first equation from the second one, is 6p³+29p²+22p-21.

Learn more about the multiplication of two equation here;

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