X - 3 is a factor because p(3) = 0
Answer:
AB=7.21 unit
BC=6 unit
CD=7.21 unit
AD= 6 unit
AC=4 unit
BD=4 unit
Step-by-step explanation:
Coordinates of A =(-2,3)
Coordinates of B = (2,-3)
Coordinates of C = (2,3)
Coordinates of D =(-2,-3)
Distance formula :

AB=7.21 unit

BC=6

CD=7.21

AD=6


AC=4

BD=
BD=4
Answer:
x = 10/3
, y = 0
Step-by-step explanation:
Solve the following system:
{4.5 x - 2 y = 15
3 x - y = 10
In the first equation, look to solve for x:
{4.5 x - 2 y = 15
3 x - y = 10
4.5 x - 2 y = (9 x)/2 - 2 y:
(9 x)/2 - 2 y = 15
Add 2 y to both sides:
{(9 x)/2 = 2 y + 15
3 x - y = 10
Multiply both sides by 2/9:
{x = (4 y)/9 + 10/3
3 x - y = 10
Substitute x = (4 y)/9 + 10/3 into the second equation:
{x = (4 y)/9 + 10/3
3 ((4 y)/9 + 10/3) - y = 10
3 ((4 y)/9 + 10/3) - y = ((4 y)/3 + 10) - y = y/3 + 10:
{x = (4 y)/9 + 10/3
y/3 + 10 = 10
In the second equation, look to solve for y:
{x = (4 y)/9 + 10/3
y/3 + 10 = 10
Subtract 10 from both sides:
{x = (4 y)/9 + 10/3
y/3 = 0
Multiply both sides by 3:
{x = (4 y)/9 + 10/3
y = 0
Substitute y = 0 into the first equation:
Answer: {x = 10/3
, y = 0
Answer:
a) No
b) No
c) P value is more than 0.05.
Step-by-step explanation:
We are given the following in the question:
Population mean, μ = 12 ounces
Sample size, n = 49
P-value = 0.136
First, we design the null and the alternate hypothesis
We use One-tailed z test to perform this hypothesis.
a) Alpha, α = 0.05
Since, p-value > α,
The null hypothesis should not be rejected. We accept the null hypothesis and reject the alternate hypothesis. We conclude that the average chip weight is 12 ounces per bag.
b) Alpha, α = 0.10
Since, p-value > α,
The null hypothesis should not be rejected. We accept the null hypothesis and reject the alternate hypothesis. We conclude that the average chip weight is 12 ounces per bag.
c) The evidence is statistically significant at the .05 level means that the p value is more than 0.05.
Set up a proportion: (1/4)/6 = 32/x
Cross multiplying, we have (1/4)x = 192
x = (4)(192) = 768 miles