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2 years ago

What is the product of (2p 7)(3p2 4p – 3)? 6p3 29p2 – 34p 21 6p3 29p2 – 22p 21 6p3 29p2 22p – 21 6p3 29p2 34p – 21

1 answer:

4 0

The product of the two provided equations, obtained by multiplying each term of the first equation from the second one, is 6p³+29p²+22p-21.

<h3>What is the product of two equations?</h3>

To multiply the two equation, each term of the first equation is multiples from the second term.

The first equation provided in the form of binomial as,

$2p+ 7$

The second equation provided in the form of quadratic equation as,

$3p^2 +4p-3$

The product of these two equations are,

$P=(2p+7)\times (3p^2 +4p-3)\\P=6p^3+8p^2-6p+21p^2+28p-21$

Arrange the equation with the same power terms,

$P=6p^3+8p^2+21p^2-6p+28p-21\\P=6p^3+29p^2+22p-21$

Hence, the product of the two provided equations, obtained by multiplying each term of the first equation from the second one, is 6p³+29p²+22p-21.

Learn more about the multiplication of two equation here;

brainly.com/question/69383

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What two perfects squares is the number 70 between

Serga [27]

Just list the perfect squares:
1
4
9
16
25
36
49
64
81
and 70 is between 64 and 81

6 0

3 years ago

How to solve exponential equation for 4^(3m-1) • 32^(2m-3) = 4

Vesna [10]

Answer:

9.5/8 = 1.1875

Step-by-step explanation:

4^(3m-1) • 32^(2m-3) = 4

4^(3m-1) • (4^2.5)^(2m-3) = 4

Law of exponents

3m-1 + 2.5(2m-3) = 1

3m - 1 + 5m - 7.5 = 1

8m = 1 + 1 + 7.5

8m = 9.5

m = 9.5/8

8 0

3 years ago

Math help plz

bija089 [108]

Answer:

I guess this is the answer hope it helps

8 0

3 years ago

there are 6 times as many ways to arrange the letters in the word "sleeplessness" as there are to arrange the letters in the wor

EastWind [94]

Using arrangements of words, it is found that the statement is true.

------------------

Suppose a word has n letters.
Considering that m of these letters are repeating, each $n_1,n_2,...,n_m$ times.
The number of distinct ways the word can be arranged is given by:

$N = \frac{n!}{n_1\times n_2 \times ... n_m}$

------------------

The word "sleeplessness" has 13 letters.
s repeats 5 times.
e repeats 4 times.
l repeats 2 times.

Thus, the number of ways to arrange the letters is given by:

$N_1 = \frac{13!}{5!4!2!}$

------------------

The word "senselessness" has 13 letters.
s repeats 6 times.
e repeats 4 times.
n repeats 2 times.

Thus, the number of ways to arrange the letters is given by:

$N_2 = \frac{13!}{6!4!2!}$

------------------

Finding the ratio of $N_2$ to $N_1$ :

$\frac{N_2}{N_1} = \frac{\frac{13!}{5!4!2!}}{\frac{13!}{6!4!2!}} = \frac{13!}{5!4!2!} \times \frac{6!4!2!}{13!} = \frac{6!}{5!} = 6$

Thus, since the ratio is 6, the statement is true.

A similar problem is given at brainly.com/question/16790460

8 0

3 years ago

Read 2 more answers

May walks a total of 3 miles to and from the library each week. She said she has walked a total of about 300 miles since she sta

Paha777 [63]

Answer:

Ok, she walks 3 miles to and from the library.

So in total, she walks 3 miles two times, then in one week, she walks 2*3mi = 6miles.

She says that she walked about 300 miles in total.

We must see if 300 miles is a multiple of 6 miles.

300mi/6mi = 50.

This means that she would walk about 300 miles since she started counting if she went to the library and back home exactly 50 times (again, since she started counting).

And she does this once a week, then if she started counting 50 weeks ago, then it is possible,

5 0

3 years ago