Can someone help me with this task please?

Mathematics

1 answer:

sesenic [268]3 years ago

6 0

Answer:

look at the picture i sent please

You might be interested in

Find the area pf a trapezoid with a base of 26.7 ft , a height of 15.4 and top of 9.9 ft

evablogger [386]

Hello!

To find the area of the trapezoid, you use the formula A=1/2h(a+b), where a and b represent the two base lengths.

Since we already know the two bases and the height, we can just plug them into the equation to find the area.

A=1/2·15.4(26.7+9.9)
A=1/2·15.4(36.6)
A=1/2·563.64
A=281.82

The area is 281.82 ft².

I hope this helps!

8 0

3 years ago

Solve the system of equations.

Sloan [31]

Answer:

( -3, -5)

Step-by-step explanation:

6x + 13 = 2x + 1

6x -2x = 1-13

4x = -12

x = -12/4 = -3

y = 6x + 13

y = 6(-3) +13 = -18+13 = -5

(x, y) = (-3,-5)

7 0

3 years ago

Read 2 more answers

If x^2+1/x^2=3 find the value of x^2/(x^2+1)^2<br> Express answer as a common fraction.<br> Thanks!!

timama [110]

$x^2+\dfrac1{x^2}=3\implies x^4+1=3x^2\implies x^4-3x^2+1=0$

By the quadratic formula,

$x^2=\dfrac{3\pm\sqrt5}2\implies x^2+1=\dfrac{5\pm\sqrt5}2$

Then

$(x^2+1)^2=\dfrac{25\pm10\sqrt5+5}4=\dfrac{15\pm5\sqrt5}2$

$\implies\dfrac{x^2}{(x^2+1)^2}=\dfrac{\frac{3\pm\sqrt5}2}{\frac{15\pm5\sqrt5}2}=\dfrac{3\pm\sqrt5}{15\pm5\sqrt5}$

Multiply numerator and denominator by the denominator's conjugate:

$\dfrac{3\pm\sqrt5}{15\pm5\sqrt5}\cdot\dfrac{15\mp5\sqrt5}{15\mp5\sqrt5}=\dfrac{45\pm15\sqrt5\mp15\sqrt5-25}{15^2-(5\sqrt5)^2}=\dfrac{20}{100}=\dfrac15$