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2 years ago

What does the frame rate of a virtual reality headset indicate brainly.

SAT

1 answer:

Anni [7]2 years ago

5 0

The frame rate of a virtual reality (VR) headset indicates: the number of images displayed per second.

<h3>What is Virtual Reality (VR) headset?</h3>

A virtual reality (VR) headset refers to a head-mounted device which consist of two LCD displays (one per eye) that provides the wearer with a view of virtual physical environments (realities) and human-machine interactions through the use of various computer technologies.

<h3>What is frame rate?</h3>

Frame rate can be defined as a a measurement of the speed at which successive images are displayed per unit of time (second).

In this context, the frame rate of a virtual reality (VR) headset indicates the number of images that are displayed per second such as 24 fps.

Read more on Virtual Reality here: brainly.com/question/26479902

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To which class class of compounds does amoniabeling to

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3 years ago

A small fruit basket with 6 apples and 6 oranges costs $7. 50. A different fruit basket with 10 apples and 5 oranges costs $8. 7

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3 years ago

In a bag of candy, Marsha found that there were 7 red, 8 blue, 5 yellow, and 9 greens pieces of candy. Marsha put all of the pie

Lunna [17]

Answer:

PART A

Red: 7/29
Blue: 8/29
Yellow: 5/29
Green: 9/29

PART B

Red or blue: 7/29 + 8/29 = 15/29
Yellow or green: 5/29 + 9/29 = 14/29
Blue or yellow or green: 8/29 + 5/29 + 9/29 = 22/29

Explanation:

In this case where the question is asking or OR and the events are mutually exclusive (Mutually exclusive meaning you can't attain two or three different colors in one pick), the compound probability is the sum of the probability of each component event (Probability of Red OR Blue = P(Red) + P(Blue) = 7/29 + 8/29 = 15/29)

8 0

3 years ago

company manufactured six television sets on a given day, and these TV sets were inspected for being good or defective. The resul

lana [24]

Sampling distribution involves the proportions of a data element in a given sample.

The proportion of Good TV set is 0.67
The number of ways of selecting 5 from 6 TV sets is 6
The number of ways of selecting 4 from 6 TV sets is 15

Given

$n = 6$

Sample Space = Good, Good, Defective, Defective, Good, Good

(a) Proportion that are good

From the sample space, we have:

$Good = 4$

So, the proportion (p) that are good are:

$p = \frac{Good}{n}$

$p = \frac{4}{6}$

$p = 0.67$

(b) Ways to select 5 samples (without replacement)

This is calculated using:

$^nC_r = \frac{n!}{(n - r)!r!}$

Where

$r = 5$

So, we have:

$^6C_5 = \frac{6!}{(6 - 5)!5!}$

$^6C_5 = \frac{6!}{1!5!}$

$^6C_5 = \frac{6 \times 5!}{1 \times 5!}$

$^6C_5 = \frac{6}{1}$

$^6C_5 = 6$

Hence, there are 6 ways

(c) All possible sample space of 4

First, we calculate the number of ways to select 4.

This is calculated using:

$^nC_r = \frac{n!}{(n - r)!r!}$

Where

$r = 4$

So, we have:

$^6C_4 = \frac{6!}{(6 - 4)!4!}$

$^6C_4 = \frac{6!}{2!4!}$

$^6C_4 = \frac{6 \times 5 \times 4}{2 \times 1 \times 4!}$

$^6C_4 = \frac{30}{2}$

$^6C_4 = 15$

So, the table is as follows:

$\left[\begin{array}{ccc}TV&Good&Proportion\\1,2,3,4&2&0.5&2,3,4,5&2&0.5&3,4,5,6&2&0.5\\4,5,6,1&3&0.75&5,6,1,2&4&1&6,1,2,3&3&0.75\\1,2,3,5&3&0.75&3,5,6,2&3&0.75&1,3,4,5&2&0.5\\1,3,4,6&2&0.5&1,4,5,2&3&0.75&2,4,6,1&3&0.75\\2,4,6,3&2&0.5&2,4,6,5&3&0.75&3,5,6,1&3&0.75\end{array}\right]$

The proportion column is calculated by dividing the number of Good TVs by the total selected (4) i.e.

$p = \frac{Good}{n}$

(d) The sampling distribution

In (a), we have:

$p = 0.67$ --- proportion of Good TV

The sampling error is calculated as follows:

$SE_n = |p - p_n|$

So, we have:

$\left[\begin{array}{ccc}TV&Good&SE\\1,2,3,4&2&0.17&2,3,4,5&2&0.17&3,4,5,6&2&0.17\\4,5,6,1&3&0.08&5,6,1,2&4&0.33&6,1,2,3&3&0.08\\1,2,3,5&3&0.08&3,5,6,2&3&0.08&1,3,4,5&2&0.17\\1,3,4,6&2&0.17&1,4,5,2&3&0.08&2,4,6,1&3&0.08\\2,4,6,3&2&0.17&2,4,6,5&3&0.08&3,5,6,1&3&0.08\end{array}\right]$

Read more about sampling distributions at:

brainly.com/question/10554762

3 0

3 years ago