Question

The width of a rectangle is 2 m less than the length. The area is 48 m. Find the dimensions

Answer 1

Answer:

$Length= 8m\\\\Width=6m$

Step-by-step explanation:

Let the length of the rectangle be 'L' meter

Width of the rectangle= (L-2 ) meter

Area of the rectangle= $48 m^2$

Area of a rectangle = length * width

$48=L*(L-2)\\\\48=L^2-2L\\\\L^2-2L-48=0$

Making the factors of the equation:

$L^2+6L-8L-48=0$

Taking common form the equation:

$L(L+6)-8(L+6)=0\\\\(L+6)(L-8)=0$

$L+6=0\\\\L=-6$

OR

$L-8=0\\\\L=8$

The length of the rectangle cannot be negative, so $Length(L)=8 m$

$Width=L-2= 8-2= 6 m$

$Length= 8m\\\\Width=6m$