A)
A=20(1.25^t)
C=25+10t
b)
A(4)=20(1.25^4)≈48.82≈49 alligators to nearest whole alligator
C(4)=25+10(4)=65 crocodiles.
c)
20(1.25^t)=25+10t
1.25^t=1.25+0.5t
t≈7
Answer:
not rlly
Step-by-step explanation:
you need more information to solve that type of equation
Answer:
reeeeeeeeeeeeeeeeeeeeeeeeee
Step-by-step explanation:
i dont
For question 1)
During the 8-9 , Mr hare travel 40miles
For the time 9 onwards they travel concurrently,
Let x be the distance covered by both since they can only meet if they covered the sams distance,
x/50 = x/40 -1 ,where the 1 is the (8-9) 1 hr
x/40 - x/50 = 1
x = 200
Time take by Mr Hare = 200/ 40 = 5
from 8 add 5 hours will be 1
ans is b
2)
during 8- 9 hare travelled 50miles
let x be the distance
x/55= x/50-1
x/50-x/55=1
x=550miles
time taken by hare = 550/50=11 hr
ie when they first meet it will be 7pm
so ans is b 8
Finding the midpoint between two points on a line involves three steps:
1. Find the distance between the two points
2. Find half of that distance
3. Either add that half to the lowest point, or subtract it from the highest point.
To find the distance between 52 and -18, we can take the absolute value of their difference. The reason we take the absolute value is to force the sign to be positive, since distances can never be negative. -18 - 52 = -70, and |-70| = 70.
Second, we find half of that distance, which in this case would be 70/2 = 35.
Finally, we add that value to -18 to find a midpoint of -18 + 35 = 17.
