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2 years ago

Evaluate the expression when у = 3 and z = 9. 2 y + (z-7)² x 2

Mathematics

1 answer:

borishaifa [10]2 years ago

5 0

Step-by-step explanation:

$y + (z - 7) {}^{2} \times 2 \\ 3 + (9 - 7) {}^{2} \times 2 \\ 3 + (2) {}^{2} \times 2 \\ 3 + 4 \times 2 \\ 3 + 8 = 11$

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Y = x + 4 y = −2x − 2

miskamm [114]

Y = x + 4
y = -2x - 2

x + 4 = -2x - 2
x + 2x = -2 - 4
3x = -6
x = -6/3
x = -2

y = x + 4
y = -2 + 4
y = 2

solution is (-2,2)

7 0

3 years ago

In the figure above, the vertices of square

Olin [163]

(C) 6 + 3√3

Explanation:

Area of the square = 3

a X a = 3

a² = 3

a = √3

Therefore, QR, RS, SP, PQ = √3

ΔBAC ≅ ΔBQR

Therefore,

$\frac{BQ}{BA} = \frac{QR}{AC}$

$\frac{BQ}{BA} = \frac{\sqrt{3} }{BA}$

In ΔBAC, BA = AC = BC because the triangle is equilateral

So,

BQ = √3

So, BQ, QR, BR = √3 (equilateral triangle)

Let AP and SC be a

So, AQ and RC will be 2a

In ΔAPQ,

(AP)² + (QP)² = (AQ)²

(a)² + (√3)² = (2a)²

a² + 3 = 4a²

3 = 3a²

a = 1

Similarly, in ΔRSC

(SC)² + (RS)² = (RC)²

(a)² + (√3)² = (2a)²

a² + 3 = 4a²

3 = 3a²

a = 1

So, AP and SC = 1

and AQ and RC = 2 X 1 = 2

Therefore, perimeter of the triangle = BQ + QA + AP + PS + SC + RC + BR

Perimeter = √3 + 2 + 1 + √3 + 1 + 2 + √3

Perimeter = 6 + 3√3

Therefore, the perimeter of the triangle is 6 + 3√3

8 0

2 years ago

If given in the following expression, find the value of

vodomira [7]

Step-by-step explanation:

Given that:

{(x²+y²)/(x²-y²)} = 17/8

On applying cross multiplication then

since, (a/b) = (c/d) ⇛a(d) = b(c)

Where, x = x²+y², b = x²-y², c = 17 and d = 8

So,

⇛17(x²-y²) = 8(x²+y²)

Multiply the number outside of the brackets with variables in the brackets on both LHS and RHS.

⇛17x²-17y² = 8x²+8y²

⇛17x²-17y² - 8x²-8y² = 0

⇛17x²- 8x² - 17y² - 8y² = 0

⇛9x² - 25y² = 0

⇛9x² = 25y²

⇛9/25 = y²/x²

⇛25/9 = x²/y²

⇛x/y = √(25/9)

⇛x/y = √{(5*5)/(3*3)}

⇛x/y = 5/3

Therefore, x:y = 5:3

Let x = 5a and y = 3a

Now, (x³+y³):(x³-y³)

= {(x³+y³)/(x³-y³)} = [{(x+y)(x²-xy+y²)}/{(x-y)(x²+x-y+y²)}]

= [{(5a)³ + (3a)³}/{(5a)³ - (3a)³}]

= [{(5*5*5*a*a*a) + (3*3*3*a*a*a)}/{(5*5*5*a*a*a) - (3*3*3*a*a*a)}]

= {(125a³ + 27a³)/(125a³ - 27a²)}

= {(152a³)/(98a³)}

= 152/98

Write the obtained fraction in lowest form by cancelling method.

= {(152÷2)/(98÷2)}

= 76/49

Therefore, , (x³+y³):(x³-y³) = 76/49

Answer: Hence, the required value of (x³+y³):(x³-y³) is 76/49.

Please let me know if you have any other questions.

6 0

2 years ago

Read 2 more answers

The athletic department raised $14,533 to buy new football uniforms if each uniform costs $258 how many uniforms can they buy

Marina CMI [18]

Answer:

56 uniforms

Step-by-step explanation:

Available amount = $14533
Cost of each uniform = $258

Number of uniforms can be bought:

14533/258 = 56 (rounded down)

Amount to be spent:

56*258 = 14448

Remaining amount:

14533 - 14448 = 85

8 0

2 years ago

-3(10) Simplify [Multiplication with integers]

Ivan

Answer:

$\boxed{\sf{-30}}$

Step-by-step explanation:

To solve this problem, all you have to do is solve by order of operations.

PEMDAS stands for:

Parenthesis
Exponents
Multiply
Divide
Add
Subtract

First, remove parenthesis.

Multiply.

-3*10

Solve.

$\sf{-3*10=\boxed{\sf{-30}}$

-30

Therefore, the correct answer is -30.

I hope this helps you! Let me know if my answer is wrong or not.

7 0

2 years ago

Read 2 more answers