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sergiy2304 [10]
1 year ago
10

At a robotics competition, robots pick up and then throw a ball. The distances, in meters, that eight robots can throw a ball ar

e recorded. Identify the outlier in the data set. Explain how you know it is an outlier.
NEEDED TODAY​

Mathematics
1 answer:
jenyasd209 [6]1 year ago
7 0

The outlier in the given data set and the reason we know it is an outlier are;

<u><em>The outlier is 9.8</em></u>

<em><u>It is an outlier because it is the distance that is less than 10.</u></em>

  • Outliers in mathematics are simply values that lie outside of the other values in a set of data. This means they are far larger than the given set of values or far smaller than the given set of values.

  • Now, in this question, we see that the distances given in meters are;

10.1 m, 10.1 m, 10.2 m, 10.2 m, 10.3 m, 10.1 m, 10.2 m, 9.8 m

  • From these set of data values, we can see that all but 1 of the values are more than 10. This number that is less than 10 is the odd one out of these set of data values and therefore it is the outlier.

Read more at; brainly.com/question/3631910

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NOOO the answer is B on EdgenA polynomial is factored using algebra tiles.

What are the factors of the polynomial?

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(x + 1) and (x − 3)

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(x + 2) and (x − 3)uity

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A movie theater is holding a contest for people who are in line before 10 p.m. The people who are within three places of the 99
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|x-99|<3

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What is 0.3 repeating as a fraction in simplest form
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a beach ball has a radius of 8 inches. find how many cubic inches to the nearest 100th of air was used to fill the beach ball
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3 years ago
P(x)=Third-degree, with zeros of −3, −1, and 2, and passes through the point (1,12).
Mila [183]

Answer:

The polynomial is:

p(x) = -x^3 - 2x^2 + 5x + 6

Step-by-step explanation:

Zeros of a function:

Given a polynomial f(x), this polynomial has roots x_{1}, x_{2}, x_{n} such that it can be written as: a(x - x_{1})*(x - x_{2})*...*(x-x_n), in which a is the leading coefficient.

Zeros of −3, −1, and 2

This means that x_1 = -3, x_2 = -1, x_3 = 2. Thus

p(x) = a(x - x_{1})*(x - x_{2})*(x-x_3)

p(x) = a(x - (-3))*(x - (-1))*(x-2)

p(x) = a(x+3)(x+1)(x-2)

p(x) = a(x^2+4x+3)(x-2)

p(x) = a(x^3+2x^2-5x-6)

Passes through the point (1,12).

This means that when x = 1, p(x) = 12. We use this to find a.

12 = a(1 + 2 - 5 - 6)

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Thus

p(x) = -(x^3+2x^2-5x-6)

p(x) = -x^3 - 2x^2 + 5x + 6

6 0
3 years ago
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