Answer:
Step-by-step explanation:
I = PRT
P = 1000
R = 2.5% or 0.025
T = 4
I = (1000)(.025)(4)
I=100
1000+100=1100
but the answer choices???
Use compound interest formula F=P(1+i)^n twice, one for each deposit and sum the two results.
For the P=$40,000 deposit,
i=10%/2=5% (semi-annual)
number of periods (6 months), n = 6*2 = 12
Future value (at end of year 6),
F = P(1+i)^n = 40,000(1+0.05)^12 = $71834.253
For the P=20000, deposited at the START of the fourth year, which is the same as the end of the third year.
i=5% (semi-annual
n=2*(6-3), n = 6
Future value (at end of year 6)
F=P(1+i)^n = 20000(1+0.05)^6 = 26801.913
Total amount after 6 years
= 71834.253 + 26801.913
=98636.17 (to the nearest cent.)
Answer:
C
Step-by-step explanation:
Answer:
0.1569 = 15.69%
Step-by-step explanation:
If eight calls were placed, and we need to know the probability of exactly two calls were occupied, we need to calculate a combination of 8 choose 2 (all the combinations of 2 occupied calls in the 8 total calls), and multiply by the probability of each case in the 8 calls (2 cases occupied and 6 cases not occupied):
P(8,2) = C(8,2) * p(occupied)^2 * p(not_occupied)^6
P(8,2) = (8*7/2) * (0.45)^2 * (0.55)^6
P(8,2) = 28 * 0.2025 * 0.02768 = 0.1569 = 15.69%
So, the anti derivative= x^2 -.8x +C. Ignore C.
Plug in 2= 4-(2)(.8)=2.4
Plug in .4= .16-(.4)(.8)=-.16
2.4-(-.16)= 2.56
