Answer:
90
12
0.0154
Step-by-step explanation:
a) #Possible experimental run=#Temp x #pres x #cat=3x5x6=90
b) #Possible experimental run=(Temp. lowest) x 2.pres x #cat=1x2x6=12
c) C="different catalyst is used on each run"
In the first, I can choice 6 of 6 catalysts, in the second 5 of 6,...
then: P(C) = 6/6 x 5/6 x 4/6 x 3/6 x 2/6 x 1/6 = 5/324 = 0.0154
What is the base salary for the Bit Labs?
Hours of training Monthly salary
10 1250
20 1400
30 1550
40 1700
50 1850
60 2000
70 2150
Answer:
-9
0
3
Step-by-step explanation:
-(-2-1)^2
-(1-1)^2
x>2 , so g(x) = 3
Answer: negative ; -144 sowwy if im wrong
Step-by-step explanation:
-4, 2, -3 , 6
-4 times -3 = -12
6 times 2 = 12
-12 times 12 = -144
Answer:
The percentage of students who scored below 620 is 93.32%.
Step-by-step explanation:
Problems of normally distributed samples are solved using the z-score formula.
In a set with mean
and standard deviation
, the zscore of a measure X is given by:

The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the pvalue, we get the probability that the value of the measure is greater than X.
In this question, we have that:

Percentage of students who scored below 620:
This is the pvalue of Z when X = 620. So



has a pvalue of 0.9332
The percentage of students who scored below 620 is 93.32%.