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Paraphin [41]
2 years ago
14

A new car is purchased for $ 33 , 000 $33,000 and over time its value depreciates by one half every 7 years. What is the value o

f the car 4 years after it was purchased, to the nearest hundred dollars?
Mathematics
1 answer:
gavmur [86]2 years ago
8 0

The equation of the value of the car over a year is 2357.14x + y = 33,000. Then the value of the car 4 years after it was purchased is $23571.43.

<h3>What is the linear system?</h3>

A Linear system is a system in which the degree of the variable in the equation is one. It may contain one, two, or more than two variables.

A new car is purchased for $33,000 and overtime its value depreciates by one half every 7 years.

Then the value of the car is given by the linear equation. Then the line is passing through (0, $33,000) and (7, $16,500). Then we have

Let y be the value of the car and x be the number of years. Then we have

\rm y \   - \  33000 \ \ = -\dfrac{16,500}{7} (x-0)\\\\y+2357.14x = 33000

Then the value of the car 4 years after it was purchased, to the nearest hundred dollars will be

\begin{aligned} \rm y +2,357.14 \times 4 &= 33,000\\\\\rm y + 9,428.57 &= 33,000\\\\\rm y &= 23,571.43 \end{aligned}

More about the linear system link is given below.

brainly.com/question/20379472

#SPJ1

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What is the correct first step to solve this system of equations by elimination?
storchak [24]

\bold{\huge{\pink{\underline{ Solution }}}}

\bold{\underline{ Given }}

  • <u>We </u><u>have </u><u>given </u><u>two </u><u>linear </u><u>equations </u><u>that</u><u> </u><u>is </u><u>2x </u><u>-</u><u> </u><u>3y </u><u>=</u><u> </u><u>-</u><u>6</u><u> </u><u>and </u><u>x</u><u> </u><u>+</u><u> </u><u>3y </u><u>=</u><u> </u><u>1</u><u>2</u><u> </u><u>.</u>

\bold{\underline{ To \: Find }}

  • <u>We </u><u>have </u><u>to </u><u>find </u><u>the </u><u>value </u><u>of </u><u>x </u><u>and </u><u>y </u><u>by </u><u>elimination </u><u>method</u><u>. </u>

\bold{\underline{ Let's \: Begin }}

\sf{ 2x - 3y = -6 ...eq(1)}

\sf{ x +  3y = 12 ...eq(2)}

<u>Multiply </u><u>eq(</u><u> </u><u>2</u><u> </u><u>)</u><u> </u><u>by </u><u>2</u><u> </u><u>:</u><u>-</u>

\sf{ 2( x + 3y = 12 )}

\sf{ 2x + 6y = 24 }

<u>Subtract </u><u>eq(</u><u>1</u><u>)</u><u> </u><u>from </u><u>eq(</u><u>2</u><u>)</u><u> </u><u>:</u><u>-</u>

\sf{ 2x + 6y -( 2x - 3y) = 24 -(-6)}

\sf{ 2x + 6y - 2x + 3y = 24 + 6 }

\sf{   9y = 30 }

\sf{   y = 30/9}

\sf{\red{ y = 10/3}}

<u>Now</u><u>, </u><u> </u><u>Subsitute</u><u> </u><u>the </u><u>value </u><u>of </u><u>y </u><u>in </u><u>eq(</u><u> </u><u>1</u><u> </u><u>)</u><u>:</u><u>-</u>

\sf{ 2x - 3(10/3) = -6 }

\sf{ 2x - 10 = -6 }

\sf{ 2x  = -6 + 10}

\sf{ x  = 4/2}

\sf{\red{ x  = 2}}

Hence, The value of x and y is 2 and 10/3

6 0
2 years ago
Ja'kniya and Alayjah are shopping at the Apple Store. Ja'kniya bought 4 screensavers and 3 Otterboxes for $29. Alayjah bought 6
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Answer:  Each screensaver costs $2 and each Otterbox costs $7.

Step-by-step explanation:

Let x = Cost of each screensaver and y = cost of each Otterbox.

As per given, 4x+3y=29       (i)

6x +2y = 26  (ii)

Divide both sides of (i) by 2 and the multiply it by 3 on sides , we get

9x+3y=39    (iii)

Eliminate (i) from (iii) , we get

5x = 10

⇒ x = 2  [Divide both sides by 5]

Put value of x in (i), we get

4(2)+3y=29

⇒ 8+3y= 29

⇒ 3y= 21

⇒ y =7 [Divide both sides by 7]

Hence, Each screensaver costs $2 and each Otterbox costs $7.

7 0
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kakasveta [241]

Answer:

the answer is 9 (^_^)

Step-by-step explanation:

6 0
3 years ago
Rewrite the expression 4+<img src="https://tex.z-dn.net/?f=%5Csqrt%7B16-%284%29%285%29%7D" id="TexFormula1" title="\sqrt{16-(4)(
Inessa05 [86]

Answer:

2+i

Step-by-step explanation:

Given the expression:

\dfrac{4+\sqrt{16-(4)(5)}}{2}

To find:

The expression of above complex number in standard form a+bi.

Solution:

First of all, learn the concept of i (pronounced as <em>iota</em>) which is used to represent the complex numbers. Especially the imaginary part of the complex number is represented by i.

Value of i =\sqrt{-1}.

Now, let us consider the given expression:

\dfrac{4+\sqrt{16-(4)(5)}}{2}\\\Rightarrow \dfrac{4+\sqrt{16-(4\times 5)}}{2}\\\Rightarrow \dfrac{4+\sqrt{16-20}}{2}\\\Rightarrow \dfrac{4+\sqrt{-4}}{2}\\\Rightarrow \dfrac{4+\sqrt{(-1)(4)}}{2}\\\Rightarrow \dfrac{4+\sqrt{(-1)}\sqrt4}{2}\\\Rightarrow \dfrac{4+\sqrt4i}{2} \ \ \ \ \ (\because \sqrt{-1} =i) \\\Rightarrow \dfrac{4+2i}{2}\\\Rightarrow 2+i

So, the given expression in standard form is 2+i.

Let us compare with standard form a+bi so we get a =2, b =1.

\therefore The standard form of

\dfrac{4+\sqrt{16-(4)(5)}}{2}

is: \bold{2+i}

8 0
3 years ago
Which statement below is always true?
STatiana [176]

Answer:

The answer is <u>B. Two parallel lines lie in the same plane.</u>

Step-by-step explanation:

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3 0
2 years ago
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