We have two unknowns: x and y. Now, we have to formulate 2 equations. The first would come from the use of the given ratio:
We use the distance formula to find the distance between coordinates:
3/4 = √[(x-4)²+(y-1)²] / √[(4-12)²+(1-5)²]
√[(x-4)²+(y-1)²] = 3√5
(x-4)²+(y-1)² = 45
x² - 8x + 16 + y² - 2y + 1 = 45
x² - 8x + y² - 2y = 28 --> eqn 1
The second equation must come from the equation of a line:
y = mx +b
m = (5-1)/(12-4) = 1/2
Substitute y=5 and x=12 for point (12,5)
5 = (1/2)(12) + b
b = -1
So, the second equation is
y = 1/2x -1 or x = 2 + 2y --> eqn 2
Solving the equations simultaneously:
(2 + 2y)² - 8(2 + 2y) + y² - 2y = 28
Solving for y,
y = -2
x = 2+2(-2) = -2
Therefore, the coordinates of point A is (-2,-2).
9/11 is rounded to 1. It rounds up because 9 is higher than 5, which is the middle of 11.
A vertical line has an equation of the form x = k, where k is the x-coordinate of all points on the line.
You have a vertical line. It passes through the point (-3, 0), so for this line, k = -3.
The vertical line has equation x = -3.
The line is dashed, not solid, so you have either < or >, but not <= or >=.
Also, notice the shading is to the left of x = -3, so all values of x are less than -3.
The inequality is
x < -3
Answer:
it's quadratic
Step-by-step explanation:
sorry i answered late but i hope this helps other people
The correct answer would most likely be 0.75n - 0.18n
