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ollegr [7]
3 years ago
15

6. A restaurant can seat 100 people. It has booths

Mathematics
1 answer:
stepan [7]3 years ago
7 0

<u>Answer:</u>

The expression  matches the situation is 4x + 6y = 80

<u>Explanation:</u>

We are given a total of 100 seats which is the maximum amount a restaurant can seat

And there are booth with 4 and table with 6 seating

so let no. of 4 seat booths be x and tables with 6 seats be y

We can form the equation as 4x + 6y = 100

We are also given that 5 of the 4 seat booths are full so this means

4\times5 = 20 seats out of 100 are full

so left ones can be written in the form of an expression 4x + 6y = 80

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2 years ago
What is 3.41 ((with 41 repeating at the end)) as a simplified fraction?
Andre45 [30]

<u>3 41/99. </u>

3.4141414...

100x= 341.4141414...

341.414141414...

- 3.41414141414..= 338

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3 years ago
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Tpy6a [65]

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3 years ago
An isotope of iodine has a mass of 134 amu. How many neutrons does the
Nina [5.8K]

Answer:

The correct option is C: the isotope of iodine contains 81 neutrons.

Step-by-step explanation:

The mass (A) of the iodine isotope is given by:

A = Z + N

Where:

Z: is the number of protons

N: is the number of neutrons

For iodine Z= 53, so if A = 134 the number of neutrons is:

N = A - Z = 134 - 53 = 81

Therefore, the correct option is C. The isotope of iodine contains 81 neutrons.

I hope it helps you!

5 0
3 years ago
In a recent study on world​ happiness, participants were asked to evaluate their current lives on a scale from 0 to​ 10, where 0
uysha [10]

Answer:

a) A response of 8.9 represents the 92nd ​percentile.

b) A response of 6.6 represents the 62nd ​percentile.

c) A response of 4.4 represents the first ​quartile.

Step-by-step explanation:

We are given the following information in the question:

Mean, μ = 5.9

Standard Deviation, σ = 2.2

We assume that the distribution of response is a bell shaped distribution that is a normal distribution.

Formula:

z_{score} = \displaystyle\frac{x-\mu}{\sigma}

a) We have to find the value of x such that the probability is 0.92

P(X < x)  

P( X < x) = P( z < \displaystyle\frac{x - 5.9}{2.2})=0.92

Calculation the value from standard normal z table, we have,  

P(z

\displaystyle\frac{x - 5.9}{2.2} = 1.405\\x = 8.991 \approx 8.9

A response of 8.9 represents the 92nd ​percentile.

b) We have to find the value of x such that the probability is 0.62

P(X < x)  

P( X < x) = P( z < \displaystyle\frac{x - 5.9}{2.2})=0.62

Calculation the value from standard normal z table, we have,  

P(z

\displaystyle\frac{x - 5.9}{2.2} = 0.305\\x = 6.571 \approx 6.6

A response of 6.6 represents the 62nd ​percentile.

c) We have to find the value of x such that the probability is 0.25

P(X < x)  

P( X < x) = P( z < \displaystyle\frac{x - 5.9}{2.2})=0.25

Calculation the value from standard normal z table, we have,  

P(z

\displaystyle\frac{x - 5.9}{2.2} = -0.674\\x = 4.4172 \approx 4.4

A response of 4.4 represents the first ​quartile.

4 0
3 years ago
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