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lora16 [44]
3 years ago
8

Solve the quadratic equation numerically (using tables of x- and y- values).

Mathematics
1 answer:
likoan [24]3 years ago
7 0

d.  x = 0 or x = -6

<h2>Explanation:</h2>

Let's say we can write a function given by the form:

y=f(x)=&#10;x(x+6)

In this case, we want to know all the y-values that makes y to be zero. In other words:

x(x+6)=0

So:

x \ \ \ \ \ 0 \ \ \ \ \ -6 \\ y \ \ \ \ \ 0 \ \ \ \ \ \ \ \ 0

The only x-values that meets this requirements are:

x=0 \\ x=-6

<h2>Learn more:</h2>

Quadratic function: brainly.com/question/12164750

#LearnWithBrainly

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Answer:

Where 0 < x < 3

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Step-by-step explanation:

The given function is f(x) = (x + 2)⁴

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At a local minimum/maximum values, we have;

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∴ (-x + 2)³ = 0

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f''(x) = \dfrac{ -4 \cdot (-x + 2)^3}{dx}  = -12 \cdot (-x + 2)^2

When x = 2, f''(2) = -12×(-2 + 2)² = 0 which gives a local minimum at x = 2

We have, f(2) = (-2 + 2)⁴ = 0

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When x = 0, -x + 2 = 0 + 2 = 2

Similarly, we have;

-x + 2 = 1, when x = 1

-x + 2 = 0, when x = 2

-x + 2 = -1, when x = 3

Therefore, the maximum value of -x + 2, is at x = 0 and the maximum value of the function where 0 < x < 3, is (0 + 2)⁴ = 16

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Answer:

y=\frac{1}{3}x +4

Step-by-step explanation:

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