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Alekssandra [29.7K]
2 years ago
15

On a straight horizontal track along which blocks can slide with negligible friction, block 1 slides toward block 2, which is in

itially at rest. Block 1 collides with an electronic force probe attached to block 2, generating a force vs. Time graph and causing block 2 to start sliding. What additional measurements must be made to determine the momentum of block 2 after the collision?
SAT
1 answer:
kiruha [24]2 years ago
5 0

The additional measurements which must be made to determine the momentum of block 2 after the collision is both the mass and the post-collision speed of block 1

<h3>What is momentum?</h3>

Momentum can be defined as a scalar quantity that involves the multiplication of the mass of an object by its velocity.

In Physics, the momentum of an object such as a block, is calculated by using this formula;

Momentum = mass × velocity

In conclusion, we can deduce that the additional measurements which must be made to determine the momentum of block 2 after the collision is both the mass and the post-collision speed of block 1.

Read more on momentum here: brainly.com/question/15517471

#SPJ1

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Among all pairs of numbers whose difference is 14 find a pair whose product is as small as possible
zvonat [6]

The pair two numbers whose difference is 14 and the product is as small as possible (i.e. -49) are (-7,7)

<h3>What are word problems?</h3>

In mathematical concepts, word problems involve a crucial understanding of the problem and knowing which mathematical method and arithmetic operations are best suited to solving the problem.

If we assume that the smaller number should be = a and the larger number = a + 14.

Thus, their product (X) can be expressed as:

= a(a+14)

= a² + 14a

The smallest possible value implies the minimum value, i.e.

\mathbf{\dfrac{dX}{da} = 2a + 14}

Thus,

2a + 14 = 0

a = - 14/2

a = -7

Therefore, we can conclude that the pair of two numbers whose difference is 14 and the product is as small as possible (i.e. -49) is (-7,7).

Learn more about word problems here:

brainly.com/question/21405634

7 0
2 years ago
Freeeee brainly points!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!
slamgirl [31]

Answer:

YESSS YESSSS FINALLY OMGGG

Explanation:

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3 years ago
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3 years ago
circle the correct terms for the reaction going from left to right. reactant a gains/loses and electron to become product B
Effectus [21]

The question requires one to indicate the correct terms for the reactant from left to right.

<h3>What is a reactant?</h3>

A reactant is a material that enters and changes during a chemical reaction.

1. Reactant A (Gains/Loses) and electron to become product B

To produce B, reactant A loses one electron. The loss of one electron from an atom causes the atom to be oxidized.

Reactant A gives an electron to NAD+ and is transformed to B+ in the given reaction there is an increase in the positive charge. As a result, reactant A is oxidized to produce B+.

2. NAD+ becomes reduced in the process of the reaction.

NAD+ receives the electron given to it by reactant A and is reduced to NADH. As a result, the positive charge of NAD+ decreases.

3. NADH is more reduced than NAD+

NAD+ receives an electron and becomes NADH. As a result, NADH is decreased more than NAD+

4. NAD+ is in the more oxidized state compared to NADH

NAD+ has a surplus of positive charge as opposed to NADH. NAD+ must receive one electron in order to produce NADH. As a result, as opposed to NADH, NAD+ is more oxidized.

5. Reactant A is the electron donor in this reaction.

Reactant A loses one electron, resulting in positively charged B+. This electron is taken up by NAD+, which reduces to NADH. As a result,  the electron donor is reactant A.

6. Reactant A is the reducing agent in this reaction.

A reducing agent is a molecule that can transfer electrons.

Such a molecule has the potential to decrease another molecule while also becoming oxidized. Reactant A is the reducing agent in the given reaction, donating an electron to NAD+.

Following the electron transfer, reactant A is oxidized to product B+, and NAD+ is reduced to NADH.

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4. 3 code practice: question 1.
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what is the question tho

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