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m_a_m_a [10]
2 years ago
10

An AC generator produces an alternating current with a peak value of 18 V. The resistance of the lamp is 4 ohms. What is the eff

ective current?​
Mathematics
1 answer:
leva [86]2 years ago
7 0

The effective current when an AC peak voltage of 18V is applied to a lamp with 4 ohm resistance is 3.18 A.

<h3>What is current?</h3>

Current is the flow of electrons through a conductor when voltage is applied across the conductor.

Given the peak voltage of 18 V, hence:

V_{rms}=\frac{Peak\ value}{\sqrt{2} } =\frac{18}{\sqrt{2} } =12.73 V\\\\I_{rms}=\frac{V_{rms}}{resistance } =\frac{12.73}{4 } =3.18 A\\

The effective current when an AC peak voltage of 18V is applied to a lamp with 4 ohm resistance is 3.18 A.

Find out more on current at: brainly.com/question/24858512

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