The effective current when an AC peak voltage of 18V is applied to a lamp with 4 ohm resistance is 3.18 A.
Current is the flow of electrons through a conductor when voltage is applied across the conductor.
Given the peak voltage of 18 V, hence:
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The answer is 84 3/8 because 672 and the left over 3 so it would be 84 3/8.
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Answer:
Area=Base length x Height
Area= O x g.
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Step-by-step explanation:
Answer:$63.30