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Scorpion4ik [409]

2 years ago

8

slide 1) Write an equation in point slope form that passes through the point (1,8) & slope of -3 y-y,=m(x-x₁) 2) Write the e

quation in slope intercept form.

1 answer:

pentagon [3]2 years ago

4 0

$(\stackrel{x_1}{1}~,~\stackrel{y_1}{8})\qquad \qquad \stackrel{slope}{m}\implies -3 \\\\\\ \begin{array}{|c|ll} \cline{1-1} \textit{point-slope form}\\ \cline{1-1} \\ y-y_1=m(x-x_1) \\\\ \cline{1-1} \end{array}\implies y-\stackrel{y_1}{8}=\stackrel{m}{-3}(x-\stackrel{x_1}{1}) \\\\\\ y-8 = -3x+3\implies y=-3x+11$

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Read 2 more answers

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cupoosta [38]

Answer:

<em></em> $\angle m + \angle t + \angle n = 180$ <em></em>

<em></em>

Step-by-step explanation:

Required

Show that:

$\angle m + \angle t + \angle n = 180^o$

To make the proof easier, I've added a screenshot of the triangle.

We make use of alternate angles to complete the proof.

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i.e.

$\angle 1 = \angle t$

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Using angle on a straight line theorem, we have:

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Rewrite as:

<em></em> $\angle m + \angle t + \angle n = 180$ <em> -- proved</em>

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