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lisabon 2012 [21]
2 years ago
14

60=-5(x-6) Please answer this with how you got the answer.

Mathematics
1 answer:
gizmo_the_mogwai [7]2 years ago
5 0

Answer:

x = -6

Step-by-step explanation:

» <u>Solution</u>

Step 1: Distribute -5 to the terms inside the parantheses.

  • (-5)(x)+(-5)(-6)=60
  • -5x+30=60

Step 2: Subtract 30 from both sides.

  • -5x+30-30=60-30
  • -5x=30

Step 3: Divide both sides by -5.

  • -5x/-5=30/-5
  • x=-6

Therefore, x = -6.

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Please answer the attachment with an answer, and tell me how to do it for brainliest, and 75 points.
lorasvet [3.4K]
1) find the mean,
               20+10+30+20+50+30+40+20/8= 27.5
2) Find the distance of each value from that mean
               20- 7.5
               10- 17.5
               30- 2.5
               20-7.5
               50- 22.5
               30- 2.5
               40- 12.5
               20- 7.5
3) Find the mean of those distances
               7.5+17.5+2.5+7.5+22.5+2.5+12.5+7.5/8=10

The Mean absolute deviation for this data set is 10.
3 0
4 years ago
Read 2 more answers
The back of a moving truck is 3 feet off of the ground. What length does a ramp off the back of the truck need to be in order fo
Marysya12 [62]

Answer:

15 feet

Step-by-step explanation:

6 0
3 years ago
Find the standard form of the equation of the parabola with a focus at (-2, 0) and a directrix at x = 2.
krok68 [10]

Answer:

y^2=\frac{1}{8}x

Step-by-step explanation:

The focus lies on the x axis and the directrix is a vertical line through x = 2.  The parabola, by nature, wraps around the focus, or "forms" its shape about the focus.  That means that this is a "sideways" parabola, a "y^2" type instead of an "x^2" type.  The standard form for this type is

(x-h)=4p(y-k)^2

where h and k are the coordinates of the vertex and p is the distance from the vertex to either the focus or the directrix (that distance is the same; we only need to find one).  That means that the vertex has to be equidistant from the focus and the directrix.  If the focus is at x = -2 y = 0 and the directrix is at x = 2, midway between them is the origin (0, 0).  So h = 0 and k = 0.  p is the number of units from the vertex to the focus (or directrix).  That means that p=2.  We fill in our equation now with the info we have:

(x-0)=4(2)(y-0)^2

Simplify that a bit:

x=8y^2

Solving for y^2:

y^2=\frac{1}{8}x

3 0
3 years ago
Use the variation of parameters method to solve the DR y" + y' - 2y = 1
postnew [5]

Answer:

y(t)\ =\ C_1e^{-2t}+C_2e^t-t\dfrac{e^{-2t}}{3}-\dfrac{1}{3}

Step-by-step explanation:

As given in question, we have to find the solution of differential equation

y"+y'-2y=1

by using the variation in parameter method.

From the above equation, the characteristics equation can be given by

D^2+D-2\ =\ 0

=>D=\ \dfrac{-1+\sqrt{1^2+4\times 2\times 1}}{2\times 1}\ or\ \dfrac{-1-\sqrt{1^2+4\times 2\times 1}}{2\times 1}

=>\ D=\ -2\ or\ 1

Since, the roots of characteristics equation are real and distinct, so the complementary function of the differential equation can be by

y_c(t)\ =\ C_1e^{-2t}+C_2e^t

Let's assume that

     y_1(t)=e^{-2t}          y_2(t)=e^t

=>\ y'_1(t)=-2e^{-2t}        y'_2(t)=e^t

   and g(t)=1

Now, the Wronskian can be given by

W=y_1(t).y'_2(t)-y'_1(t).y_2(t)

   =e^{-2t}.e^t-e^t(-e^{-2t})

   =e^{-t}+2e^{-t}

   =3e^{-t}

Now, the particular solution can be given by

y_p(t)\ =\ -y_1(t)\int{\dfrac{y_2(t).g(t)}{W}dt}+y_2(t)\int{\dfrac{y_1(t).g(t)}{W}dt}

=\ -e^{-2t}\int{\dfrac{e^t.1}{3.e^{-t}}dt}+e^{t}\int{\dfrac{e^{-2t}.1}{3.e^{-t}}dt}

=\ -e^{-2t}\int{\dfrac{1}{3}dt}+\dfrac{e^t}{3}\int{e^{-t}dt}

=\dfrac{-e^{-2t}}{3}.t-\dfrac{1}{3}

=-t\dfrac{e^{-2t}}{3}-\dfrac{1}{3}

Now, the complete solution of the given differential equation can be given by

y(t)\ =\ y_c(t)+y_p(t)

      =C_1e^{-2t}+C_2e^t-t\dfrac{e^{-2t}}{3}-\dfrac{1}{3}

5 0
3 years ago
The length of the diagonal of a square is 30square root 2 find the perimeter of the square
RoseWind [281]

Answer:

120.

Step-by-step explanation:

Using the Pythagoras theorem:

(30√2)^2 = x^2 + x^2         where x =length of each side of the square

1800 = 2x^2

x^2 = 900

x = 30.

So the perimeter = 4*30 = 120.

5 0
3 years ago
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