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lisabon 2012 [21]

2 years ago

14

60=-5(x-6) Please answer this with how you got the answer.

1 answer:

gizmo_the_mogwai [7]2 years ago

5 0

Answer:

x = -6

Step-by-step explanation:

» <u>Solution</u>

Step 1: Distribute -5 to the terms inside the parantheses.

$(-5)(x)+(-5)(-6)=60$
$-5x+30=60$

Step 2: Subtract 30 from both sides.

$-5x+30-30=60-30$
$-5x=30$

Step 3: Divide both sides by -5.

$-5x/-5=30/-5$
$x=-6$

Therefore, x = -6.

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Darryl and Kayla sold pies for a school fundraiser. Darryl made $38 from 2 chocolate pies and 4 apple pies. Kayla made $138 from

katrin2010 [14]

Answer:

$3

Step-by-step explanation:

let the cost of apple pie be $x$ and the cost of chocolate pie be $y$ .

We then express the situation as:

$2y+4x=38\ \ \ \ \ \ ...eqtn1\\\\14y+12x=138\ \ \ \....eqtn2$

#Make y the subject of the formula in equation 1 then substitute in 2:

$2y=38-4x\\y=19-2x\\\\\therefore 14(19-2x)+12x=138\\\ \ 266-28x+12x=138\\\ \ 128=16x\\x=8\\\\y=19-2\times8=3$

Hence, the cost of a chocolate pie is $3

3 0

4 years ago

The diameter of a circle is 8 ft. Find its area in terms of pi

WITCHER [35]

Answer:

16π

Step-by-step explanation:

Area = πr²

r - radius

r = d/2 = 8/2 =4

Area = 4²π = 16π

3 0

4 years ago

Read 2 more answers

Trig proofs with Pythagorean Identities.

lorasvet [3.4K]

To prove:

$$\frac{1}{1-\cos x}-\frac{\cos x}{1+\cos x}=2 \cot ^{2} x+1$

Solution:

$$LHS = \frac{1}{1-\cos x}-\frac{\cos x}{1+\cos x}$

Multiply first term by $\frac{1+cos x}{1+cos x}$ and second term by $\frac{1-cos x}{1-cos x}$ .

$$= \frac{1(1+\cos x)}{(1-\cos x)(1+\cos x)}-\frac{\cos x(1-\cos x)}{(1+\cos x)(1-\cos x)}$

Using the identity: $(a-b)(a+b)=(a^2-b^2)$

$$= \frac{1+\cos x}{(1^2-\cos^2 x)}-\frac{\cos x-\cos^2 x}{(1^2-\cos^2 x)}$

Denominators are same, you can subtract the fractions.

$$= \frac{1+\cos x-\cos x+\cos^2 x}{(1^2-\cos^2 x)}$

Using the identity: $1-\cos ^{2}(x)=\sin ^{2}(x)$

$$= \frac{1+\cos^2 x}{\sin^2x}$

Using the identity: $1=\cos ^{2}(x)+\sin ^{2}(x)$

$$=\frac{\cos ^{2}x+\cos ^{2}x+\sin ^{2}x}{\sin ^{2}x}$

$$=\frac{\sin ^{2}x+2 \cos ^{2}x}{\sin ^{2}x}$ ------------ (1)

$RHS=2 \cot ^{2} x+1$

Using the identity: $\cot (x)=\frac{\cos (x)}{\sin (x)}$

$$=1+2\left(\frac{\cos x}{\sin x}\right)^{2}$

$$=1+2\frac{\cos^{2} x}{\sin^{2} x}$

$$=\frac{\sin^2 x + 2\cos^{2} x}{\sin^2 x}$ ------------ (2)

Equation (1) = Equation (2)

LHS = RHS

$$\frac{1}{1-\cos x}-\frac{\cos x}{1+\cos x}=2 \cot ^{2} x+1$

Hence proved.

5 0

4 years ago

8. Una receta para hacer dulce de membrillo indica que la cantidad de fruta debe

Paladinen [302]

Answer:

1.67 kilogramos de azúcar

6 0

3 years ago

BRAINLIESSTTTT ASAP !!!!!!!!!!

Tanzania [10]

9x^2 + 24 x + 16 = 0

(3x +4) (3x + 4) = 0

x=-4/3

are you sure part A doesn't have a negative somewhere?

9x^2+12x+12x+16 this works just double checking

b)

16x^2 - 25y^2 = 0

(4x-5y)(4x+5y)= 0

hope this helps

8 0

4 years ago