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miss Akunina [59]
3 years ago
9

Darryl and Kayla sold pies for a school fundraiser. Darryl made $38 from 2 chocolate pies and 4 apple pies. Kayla made $138 from

14 chocolate pies and 12 apple pies. How much was a chocolate pie?
Mathematics
1 answer:
katrin2010 [14]3 years ago
3 0

Answer:

$3

Step-by-step explanation:

let the cost of apple pie be x and the cost of chocolate pie be y.

We then express the situation as:

2y+4x=38\ \ \ \ \ \ ...eqtn1\\\\14y+12x=138\ \ \  \....eqtn2

#Make y the subject of the formula in equation 1 then substitute in 2:

2y=38-4x\\y=19-2x\\\\\therefore 14(19-2x)+12x=138\\\ \ 266-28x+12x=138\\\ \ 128=16x\\x=8\\\\y=19-2\times8=3

Hence, the cost of a chocolate pie is $3

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The volume of a cube is V=x³ where x is the side length. The volume of a cube can also be written as V=lwh, where l is length, w is width and h is height. since the given side length to us is 9.2, we can put that into the formula. 
V=9.2³, or V=9.2*9.2*9.2
V=778.688in³

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Angelo cuts a triangle from a sheet of paper as shown. what is the measure of the triangle?
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Http://prntscr.com/anjh06

The image I saw was a paper with 90° edges. the 90° was cut into 2, 75° and x.

x = 90° - 75° = 15°

Interior angles of a triangle should equal 180°. The other corner of the paper is part of the triangle. It has a measure of 90°

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3rd angle = 180° - 105°
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I have no idea how to do this, it is due in two days. Hopefully someone sees this before then.
elena-14-01-66 [18.8K]

Hello,

m\ \widehat{ABC}=x\\m\ \widehat{BAC}=2*x\\\\So:\\ x+2x=90^o\\x=30^o\\

cos(30^o)=\dfrac{\sqrt{3} }{2} \\

In the triangle ABC,

cos(30^o)=\frac{BC}{BA} \\\\BA=\dfrac{cos(30^o)}{BC} \\\\BA=\frac{\dfrac{\sqrt{3} }{2} }{24} =16*\sqrt{3} \\\\

sin(30^o)=\dfrac{1 }{2} =\dfrac{AC}{AB} \\\\AC=\dfrac{1}{2} *16\sqrt{3} =8\sqrt{3}

In the triangle ACB,

cos(30^o)=\dfrac{AC}{AL} \\\\AL=\dfrac{8\sqrt{3} *2}{\sqrt{3} } =16\\

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3 years ago
PLEASE SOMEONE HELP ME WITH THESE QUESTIONS I'VE BEEN STUCK ON HERE FOR SO LONG​
Neporo4naja [7]

Answer:

# means number

Step-by-step explanation:

Distance = Y-axis or output

Cost= X-axis or input

you do not need to add the brackets for the formula(BEDMAS), but it makes things clearer

For A -

the Y-intercept is where the first coordinate, or the # or the X-axis, is 0 (on the graph the y-intercept 0,4)

For B -

y = mx + b

m =  slope

x = input or # on the X-axis

b = y-intercept

or

formula = (input x increase in the slope) + output for 0 or (distance x increase in cost) + output for 0

input(x axis)         output(y axis)

0                 5    ← output for 0

1                  9  

2                 13

there is a +4 increase in the slope, the increase in the slope is an output #(in this case 9) - the previous output number (in this case 5)

formula = (input x increase in the slope) + output for 0 = distance

formula in use = (3 x 4) + 5 = 17

For C:

The dependent variable is the output or the cost because the input or the distance will determine the cost travelled. Eg. if I travel 9 miles it will cost $41. If the dependent variable is the cost then the independent variable is the distance

For D: (input x increase in the slope) + output for 0

(4.2 miles x $4) + 5

16.8 + 5 = $21.8; It will cost $21.8 to travel 4.2miles

For E: (distance x increase in cost) + output for 0

(? x 4) + 5 = 14

(14 - 5) = 9

9 ÷ 4 = 2.25miles; with 14 dollars I could travel 2.25 miles

(It is a bit confusing lol, but this is the way I understand it, if you can't understand it this way then use y = mx + b)

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so 480 divided by 18 = about 27

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