Answer:


Step-by-step explanation:
Given: See Attachment
Required
Determine the length of the legs
To do this, we apply Pythagoras theorem.

In this case:

Open Bracket



Collect Like Terms


Solving using quadratic formula:

So:
or 
Since, x can't be negative, then:

One of the leg is:






Answer:
30
Step-by-step explanation:
a^2 + b^2 = c^2
(8sqrt(3))^2 + b^2 = 16^2
64 * 3 + b^2 = 256
192 + b^2 = 256
b^2 = 64
b = 8
The ratio of the lengths of the sides of this triangle is
8 : 8sqrt(3) : 16
which reduces to
1 : sqrt(3) : 2
This is the ratio of the lengths of the sides of a 30-60-90 triangle.
m<W = 30 deg
Answer:
3
lazy approach was with a graphic plotting program, but you can also calculate it. with the pq-formula.
p = -6
q = 9
x = -p/2 +- sqrt( (p/2)² - q)
x = -(-6)/2 +- sqrt ( (-6/2)² - 9)
x = 3 +- sqrt(9-9)
x = 3 +- sqrt(0)
x = 3 +- 0
x = 3
Answer:
y = 2.5 + 4.75, every additional rose sold , x, increases the cost of the rose, y, by 2.50
Step-by-step explanation:
(B)
if <em>f</em>(a) = K, then that means <em>f </em>sends (a) to (K).
the inverse function, <em>f</em>-1, goes back where you started, so <em>f</em>-1 <em />sends (K) to (a).
<em>f</em>-1(K) = a.