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3 years ago

WILL GIVE A BRAINLIEST

1 answer:

4 0

Find slope
slope betwen 2 points (x1,y1) and (x2,y2) is (y2-y1)/(x2-x1)

so
first make denoms same
denom is 10
(4/5,1/5) turns to (8/10,2/10)
(1/2,3/2) turns to (5/10,15/10)
slope=(15/10-2/10)/(5/10-8/10)=(13/10)/(-3/10)=13/-3=-13/3

use point slope
use (4/5,1/5)
y-y1=m(x-x1)
a point is (x1,y1) and slope is m
y-1/5=-13/3(x-4/5)
expand
wait, we don't need to do that, the only one with slope -13/3 is D
answer is D

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PLEASE HELP ASAP!!! CORRECT ANSWER ONLY PLEASE!!! What is (f/g)(x) ?

Rudiy27

Answer: $\bold{D.\ \dfrac{x+4}{x}\ where\ x \neq 0, \dfrac{2}{3}}$

Step-by-step explanation:

f(x) = 3x² + 10x - 8

g(x) = 3x² - 2x

$\dfrac{f(x)}{g(x)}=\dfrac{3x^2+10x-8}{3x^2-2x}=\dfrac{(3x-2)(x+4)}{x(3x-2)}=\dfrac{x+4}{x}$

Restriction on x: the denominator cannot be equal to zero. So,

x(3x - 2) ≠ 0

→ x ≠ 0 and 3x - 2 ≠ 0

3x ≠ 2

x $\neq \dfrac{2}{3}$

8 0

3 years ago

Christine Wong has asked Dave and Mike to help her move into a new apartment on Sunday morning. She has asked them both in case

olga nikolaevna [1]

Answer:

(a) The probability that both Dave and Mike will show up is 0.25.

(b) The probability that at least one of them will show up is 0.75.

Step-by-step explanation:

Denote the events as follows:

D = Dave will show up.

M = Mike will show up.

Given:

$P(D^{c})=0.55\\P(M^{c})=0.45$

It is provided that the events of Dave of Mike showing up are independent of each other.

(a)

Compute the probability that both Dave and Mike will show up as follows:

$P(D\cap M)=P(D)\times P (M)\\=[1-P(D^{c})]\times [1-P(M^{c})]\\=[1-0.55]\times[1-0.45]\\=0.2475\\\approx0.25$

Thus, the probability that both Dave and Mike will show up is 0.25.

(b)

Compute the probability that at least one of them will show up as follows:

P (At least one of them will show up) = 1 - P (Neither will show up)

$=1-P(D^{c}\cup M^{c})\\=P(D\cup M)\\=P(D)+P(M)-P(D\cap M)\\=[1-P(D^{c})]+[1-P(M^{c})]-P(D\cap M)\\=[1-0.55]+[1-0.45]-0.25\\=0.75$

Thus, the probability that at least one of them will show up is 0.75.

(c)

Compute the probability that neither Dave nor Mike will show up as follows:

$P(D^{c}\cup M^{c})=1-P(D\cup M)\\=1-P(D)-P(M)+P(D\cap M)\\=1-[1-P(D^{c})]-[1-P(M^{c})]+P(D\cap M)\\=1-[1-0.55]-[1-0.45]+0.25\\=0.25$

Thus, the probability that neither Dave nor Mike will show up is 0.25.

6 0

3 years ago

Read 2 more answers

Please answer this correctly

erastovalidia [21]

The right answer is 40 cm

please see the attached picture for full solution

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8 0

3 years ago

Help will make you as brain plssss

saul85 [17]

Answer:

answer is 19.

Step-by-step explanation:

see picture for explanation.

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7 0

3 years ago

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ASAP!! Please help me. I will not accept nonsense answers, but will mark as BRAINLIEST if you answer is correctly with solutions

EleoNora [17]

Answer:

Option C is the correct option.

Step-by-step explanation:

$f(x) = a {x}^{2} + bx + c$

Discriminant = ${b}^{2} - 4ac$

Given d = 15

When discriminant D > 0 --> roots are real and distinct. ( unequal )

So , ${3}^{rd}$ option has real and distinct roots.

Hope this helps..

Best regards!!

4 0

3 years ago