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Mademuasel [1]
2 years ago
12

Select the correct answer from each drop-down menu.

Mathematics
1 answer:
RSB [31]2 years ago
5 0

Evidence are simply facts to support a claim, while counterexamples are instances to show the contradictions in a claim

<em>The question is incomplete, as the required drop-down menus are missing. So, I will give a general explanation</em>

<em />

To show that a statement is true, you need evidence.

Take for instance:

\mathbf{if\ a^2 = 4,\ then\ a = 2}

The evidence that the above proof is true is by taking the <em>squares of both sides of </em>\mathbf{a = 2}

\mathbf{a^2 = 2^2}

\mathbf{a^2 = 4}

However, a counterexample does not need a proof per se.

What a counterexample needs is just an instance or example, to show that:

\mathbf{if\ a^2 = 4,\ then\ a \ne 2}

An instance to prove that: \mathbf{if\ a^2 = 4,\ then\ a = 2} is false is:

\mathbf{a = -2}

Hence, the complete statement could be:

<em>In a direct proof, evidence is used to support a proof . On the other hand, a counterexample is a single example that shows that a proof is false.</em>

<em />

Read more about evidence and counterexample at:

brainly.com/question/88496

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Angela invested $4000 in an account that earns 5% interest yearly (simple interest). She forgets about it for 12 years. What is
harina [27]

Answer:

$6400

Step-by-step explanation:

4000x.05=200× 12=2400+4000=$6400

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3 years ago
3. A copy machine makes 60 copies per minute. A second
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E

Step-by-step explanation:

6 x 480 + 8 x 60 = 960..........

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3 years ago
1. Using the above
Ivan

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yes there is a correlation

Step-by-step explanation:

here's how I found this by looking up all key words.

4 0
2 years ago
The national mean annual salary for a school administrator is $90,00 a year (The Cincinnati Enquirer, April 7, 2012). A school o
timurjin [86]

Answer:

a) Null hypothesis:\mu = 90000  

Alternative hypothesis:\mu \neq 90000  

b) p_v =2*P(t_{(24)}  

c) If we compare the p value and the significance level given \alpha=0.05 we see that p_v so we can conclude that we have enough evidence to reject the null hypothesis, so we can conclude that the true mean for the salary differs from 9000 at 5% of significance.

Step-by-step explanation:

1) Data given and notation  

77600 ,76000 ,90700 ,97200 ,90700 ,101800 ,78700 ,81300 ,84200 ,97600 ,

77500 ,75700 ,89400 ,84300 ,78700 ,84600 ,87700 ,103400 ,83800 ,101300

94700 ,69200 ,95400 ,61500 ,68800

We can calculate the sample mean and deviation with the following formulas:

\bar X =\frac{\sum_{i=1}^n X_i}{n}

s=\sqrt{\frac{\sum_{i=1}^n (X_i -\bar X)^2}{n-1}}

The values obtained are:

\bar X=85272 represent the mean annual salary for the sample  

s=11039.23 represent the sample standard deviation for the sample  

n=25 sample size  

\mu_o =90000 represent the value that we want to test

\alpha=0.05 represent the significance level for the hypothesis test.  

t would represent the statistic (variable of interest)  

p_v represent the p value for the test (variable of interest)  

Part a: State the null and alternative hypotheses.  

We need to conduct a hypothesis in order to check if the mean salary differs from 90000, the system of hypothesis would be:  

Null hypothesis:\mu = 90000  

Alternative hypothesis:\mu \neq 90000  

If we analyze the size for the sample is < 30 and we don't know the population deviation so is better apply a t test to compare the actual mean to the reference value, and the statistic is given by:  

t=\frac{\bar X-\mu_o}{\frac{s}{\sqrt{n}}}  (1)  

t-test: "Is used to compare group means. Is one of the most common tests and is used to determine if the mean is (higher, less or not equal) to an specified value".  

Part b: Calculate the statistic

We can replace in formula (1) the info given like this:  

t=\frac{85272-90000}{\frac{11039.23}{\sqrt{25}}}=-2.141    

P-value

The first step is calculate the degrees of freedom, on this case:  

df=n-1=25-1=24  

Since is a two sided test the p value would be:  

p_v =2*P(t_{(24)}  

Part c: Conclusion  

If we compare the p value and the significance level given \alpha=0.05 we see that p_v so we can conclude that we have enough evidence to reject the null hypothesis, so we can conclude that the true mean for the salary differs from 9000 at 5% of significance.

6 0
3 years ago
Ten times as much as 3000
chubhunter [2.5K]

Multiply 3000 by 10

10*3000=30000

3 0
3 years ago
Read 2 more answers
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