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Svetradugi [14.3K]
3 years ago
7

Line 1 passes through the points (-4, -6) and (12,2). line 2 passes through the points (-6,-2) and (-2,0). Do the lines intersec

t?
(Can someone make a graph?)
Mathematics
1 answer:
kifflom [539]3 years ago
7 0

The lines dont intersect

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Help me with this please!!!!!!!!!!
aleksandr82 [10.1K]

Answer:

B)  (8, 0) and (-4,0)

Step-by-step explanation:

x-intercept when y = 0

so

x^2 - 4x - 32 = 0

Factors

(x - 8)(x + 4 ) = 0

x - 8 = 0; x = 8

x + 4 = 0; x = -4

(8, 0) and (-4,0)

5 0
3 years ago
4. The figures below are similar. What is
RideAnS [48]

Answer:

20 but I am not sure.....

4 0
3 years ago
Read 2 more answers
6p+2+ p - 3 = 8p - 8​
saul85 [17]
6p+p+2-3=8p-8
7p-1=8p-8
1=1p-8
7=1p
p=7
7 0
3 years ago
Find the circumference of a circle with diameter,
Pavlova-9 [17]

Answer:

6π cm

Step-by-step explanation:

5 0
3 years ago
Read 2 more answers
part 2. Find the value of the trig function indicated, use for that Pythagorean theorem to find the third side if you need it.​
andreev551 [17]

Answer:  \bold{5)\ \cos \theta=\dfrac{\sqrt{11}}{6}\qquad 6)\ \tan \theta =\dfrac{8}{17}\qquad 7)\ \cos \theta = \dfrac{4}{3}\qquad 8)\ \cos \theta = \dfrac{\sqrt{10}}{10}}

<u>Step-by-Step Explanation:</u>

Pythagorean Theorem is: a² + b² = c²  , <em>where "c" is the hypotenuse</em>

5)\ \cos \theta=\dfrac{\text{side adjacent to}\ \theta}{\text{hypotenuse of triangle}}=\dfrac{3\sqrt{11}}{18}\quad \rightarrow \large\boxed{\dfrac{\sqrt{11}}{6}}

Note: (15)² + (3√11)² = hypotenuse²   →   hypotenuse = 18

6)\ \cos \theta=\dfrac{\text{side adjacent to}\ \theta}{\text{hypotenuse of triangle}}=\dfrac{8}{17}\quad =\large\boxed{\dfrac{8}{17}}

Note: 8² + 15² = hypotenuse²   →   hypotenuse = 17

7)\ \tan \theta=\dfrac{\text{side opposite to}\ \theta}{\text{side adjacent to}\ \theta}=\dfrac{20}{15}\quad \rightarrow \large\boxed{\dfrac{4}{3}}

Note: hypotenuse not needed for tan

8)\ \cos \theta=\dfrac{\text{side adjacent to}\ \theta}{\text{hypotenuse of triangle}}=\dfrac{2}{2\sqrt{10}}\quad =\large\boxed{\dfrac{\sqrt{10}}{10}}

Note: 2² + 6² = hypotenuse²   →   hypotenuse = 2√10

8 0
3 years ago
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