Let x and y be width and length of the plot to be fenced. Therefore,
Area (A) = xy m^2
If the side bordering the river is x, then
Circumference (C) = 8500 = x+2y => x = 8500-2y
Substituting for w in the equation for A;
A = (8500-2y)y = 8500y -2y^2
For maximum area, derivative of A with respect to y is 0. That is;
dA/dy = 0 = 8500 -4y => 4y = 8500 => y = 8500/4 = 2125 m
And, x = 8500-2y = 8500 -2*2125 = 4250 m
Therefore,
One side = 4,250 m and second side = 2,125 m.
Largest area, A = 4250*2125 = 9,031,250 m^2
We have events:

- a <span>student stays in the school's dormitory

- </span>a <span>student stays with family

- </span><span>a student receives As
and </span> probabilities:

We want to calculate the probability <span>that the student lives in the school dormitory given he </span><span>receives As so it will be </span>

. From the <span>Bayes' theorem we know that:

The only thing we don't know is

, but we can calculate it using the l</span><span>aw of total probability. There will be:

So our probability:

Answer D.
</span>
Answer:
18m+20
Step-by-step explanation:
9m(2)+10(2)=18m+20
Answer:
the answer is (-3,4) hope this helps
Step-by-step explanation: