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grandymaker [24]
2 years ago
12

Make sure you click the image for full picture

Mathematics
2 answers:
Ivanshal [37]2 years ago
8 0

question 19

equal to: 3's

less than: 2's, 1's

greater than: 0's

question 20

40 gallons, 12 concentrate, 28 water

this is a fraction of 12/28

simplification: (12) divided by 12 / (28) divided by 12

1/2

1 part concentrate 2 parts water per each of the 40 total gallons.

so color in 33% for concentrate and 66% water

I am totally not wrong  :D:D:D:D

Assoli18 [71]2 years ago
4 0

Answer:

See below.

Step-by-step explanation:

19.

The spinner has 12 equal-sized sections.

1/3 of 12 = 4

A number that appears in exactly 4 sections has a probability of 1/3. The number 3 appears exactly 3 times.

A number that appears more than 4 times has a probability greater than 1/3. The number 0 appears exactly 5 times.

A number that appears fewer that 4 times has a probability of less than 1/3.

Both 1 and 2 appear fewer than 4 times.

Answer:

Probability greater than 1/3: 0

Probability equal to 1/3: 3

Probability less that 1/3: 1, 2

20.

The amount of concentrate is 12 gallons.

The total amount of drink is 40 gallons.

The fraction of the concentrate out of the total is 12/40.

12/40 = 0.3

0.3 of each gallon is concentrate.

Color the bottom up to 0.30

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109

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Find the surface area and volume of each figure. Round each answer to the nearest hundredth.
Llana [10]

Answer: Surface area is equal to 200cm^{2}

Volume is equal to 333.33cm^{3}

Step-by-step explanation:

First, let's do surface area.

The surface area of a pyramid is equal to 1/2(perimeter of base)(lateral height) + area of the base

The perimeter of the base is 10(4) = 40; as the base is a square with a side length of 10.

The lateral height is given as 5 cm.

The area of the base is 10(10) = 100.

We can plug those numbers into the equation to get 1/2(40)(5) + 100, which comes out to be 200cm^{2}.

Now for volume.

The volume of a pyramid is equal to 1/3(area of the base)(height).

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Hope this helps!

6 0
3 years ago
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Find parametric equations and symmetric equations for the line. (Use the parameter t.) The line through (4, −5, 2) and parallel
Nataliya [291]

Answer:

Step-by-step explanation:

From the given information, the symmetric equations for the line pass through(4, -5, 2) i.e (x_o, y_o, z_o) and are parallel to \dfrac{x+5}{1} = \dfrac{y}{2}= \dfrac{z-3}{1}

The parallel vector to the line i + zj+k = ai + bj + ck

Hence, the equation for the line is :

x = x_o + at \\ \\ x = y_o + bt \\ \\ x = z_o + ct

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Thus, x, y, z = ( 4+t, -5+2t, 2+t )

The symmetric equation can now be as follows:

\begin  {vmatrix} x = 4+ t   \\ \\  \dfrac{x-4}{1} = t  \begin {vmatirx} \end {vmatrix}\begin {vmatrix} y = - 5+2t  \\ \\ \dfrac{y+5}{2}  =t      \end {vmatrix}\begin {vmatrix} z =2+t  \\ \\ \dfrac{z-2}{1}  =t      \end {vmatrix}

∴

\dfrac{x-4}{1}= \dfrac{y+5}{2}=\dfrac{z-2}{1}

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3 years ago
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