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jek_recluse [69]
2 years ago
12

Using a 10' long piece of strut as a straightedge, you are trying to determine the outside diameter of a grain storage silo. You

and your partner very carefully measure from the ends of the straightedge, squarely, in to the wall of the silo and find that the “H” distance is 14 3/4" at both ends. What is the radius of the silo in inches? Note: The values calculated for this question may be used for additional questions. (Round the answer to the nearest 1/8".)
Mathematics
1 answer:
Vesna [10]2 years ago
4 0

The radius of the silo is the distance from its center to the outside wall

The radius of the silo is 7 3/8" or 7 3/8 inches

<h3>How to determine the radius?</h3>

From the question, we have the following parameters:

  • Length of strut = 10'
  • Outside diameter of silo = 14 3/4"

The radius is then calculated as:

Radius = 0.5 * Diameter

This gives

Radius = 0.5 * 14 3/4"

Evaluate the product

Radius = 7 3/8"

Hence, the radius of the silo is 7 3/8" or 7 3/8 inches

Read more about radius at:

brainly.com/question/1029327

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If your dog eats 7/8 lb of food in 4 meals,how many meals will take your dog to eat 1 lb of food
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Select the correct answer from each drop-down menu.
finlep [7]

Answer:

Coordinates of point B are (10,-4)

Coordinates of point D are (3.6,-0.4)

Step-by-step explanation:

1) Point C(3.6, -0.4) divides in the ratio 3 : 2. If the coordinates of A are (-6, 5), the coordinates of point B are ____

Let the coordinates of B be (x_2,y_2)

Coordinates of A =(x_1,y_1)=(-6,5)

Coordinates of C=(x,y)=(3.6,-0.4)

We will use section formula over here

x=\frac{mx_2+nx_1}{m+n} , y = \frac{my_2+ny_1}{m+n}

m:n=3:2

3.6=\frac{3x_2+2(-6)}{3+2} , -0.4=\frac{3y_2+2(5)}{3+2}3.6 \times 5 = 3x_2-12, -0.4 \times 5 = 3y_2+10\\18+12=3x_2 , -2=3y_2+10\\30=3x_2 , -12=3y_2\\10=x_2, -4=y_2\\

Coordinates of B = (10,-4)

2)If point D divides in the ratio 4 : 5, the coordinates of point D are ____

(fraction)

Let the coordinates of D be (x,y)

Coordinates of A =(x_1,y_1)=(-6,5)

Coordinates of B=(x_2,y_2)=(10,-4)

We will use section formula over here

x=\frac{mx_2+nx_1}{m+n} , y = \frac{my_2+ny_1}{m+n}

m:n=3:2

x=\frac{3(10)+2(-6)}{3+2} , y=\frac{3(-4)+2(5)}{3+2}\\x=3.6,y=-0.4

Coordinates of point B are (10,-4)

Coordinates of point D are (3.6,-0.4)

4 0
3 years ago
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