Answer:
Step-by-step explanation:
2 functions start by making a domain
Function 1: -3≤x<1
Function 2: -1≤x≤1
Now come up with equations
Function 1= x+3
Function 2= 5
Now put it all together
f(x)= x+3 for -3≤x<1 and 5 for -1≤x≤1
(2m + 7) - (3 - 4m)
First distribute the (-) in front of the quantity of 3 - 4m.
Think of it as this:
-1(3 - 4m)
You multiply each number inside the parenthesis by -1.
So:
3*-1 = -3
-4m * -1 = 4m
Now that you've distributed the negative you can remove the parenthesis.
Now you'll just set it all up like you would any normal problem. Because -3 is negative you'll make it subtract.... I'll show you what I mean:
2m + 7 - 3 + 4m
Combine like terms (Terms which have the same variables... in this case the same number of m's)
Rearranging them can help!
4m + 2m + 7 - 3
6m + 7 - 3
6m + 4, is our difference!
Answer:
Two-tailed test.
Step-by-step explanation:
There are two types of tests:
One-tailed tests and two-tailed tests.
When we only test if the mean is less or more than a value, we have a one-tailed test.
When we test if the mean is different from a value, we have a two-tailed test.
If you were to conduct a test to determine whether there is evidence that the proportion is different from 0.30, which test would you use?
Test if it is different, so a two-tailed test.
