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m_a_m_a [10]
3 years ago
10

Please help! <3

Mathematics
1 answer:
igomit [66]3 years ago
3 0

Answer:

8 square units

Step-by-step explanation:

Area of a rectangle= lenght x width

locating the four points on a Cartesian plane

lenght = BC= AD = (0,4)->(4,4) = 4units

width = AB = CD = (0,2)-> (0,4) = 2units

Area of rectangle = 4units x 2units = 8 square units

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NEED ASAP!!!
k0ka [10]

Answer:

N = 3

Step-by-step explanation:

If 6 = 1 and n = 1/2 then n is 1/2 of 6

6/2 = 3

4 0
3 years ago
A family has two cats named Gordo and Flaco. Gordo weighs 15 pounds and Flaco weighs 8 pounds. A cat’s weight is classified as u
Elena-2011 [213]

Answer:

Gordo's weight = 15 pounds

It is outside the healthy weight range and is in the top 5% of weights of cats.

Gordo's weight makes Gordo unhealthy.

Step-by-step explanation:

μ = mean weight = 9.5 pounds

σ = standard deviation = 1.5 pounds

This is a normal distribution problem

We first calculate the limit of the bottom 5% of weights

Let the z-score for this limit be z'

P(z < z') = 0.05

From the normal distribution table,

z' = -1.645

And the limit for the top 5% which is z" = 1.645.

The weight that corresponds to these scores are then calculated.

Standardized scores are given as

z = (x - μ)/σ

So,

z' = (limit for the bottom 5% - μ)/σ

-1.645 = (limit for the bottom 5% - 9.5)/1.5

limit of the bottom 5% = (-1.645)(1.5) + 9.5 = 7.033 pounds

z" = ( (limit for the top 5% - μ)/σ

1.645 = (limit for the top 5% - 9.5)/1.5

limit of the bottom 5% = (1.645)(1.5) + 9.5 = 11.968 pounds

Therefore the healthy weight range for cats is (7.033 < x < 9.968)

Gordo's weight = 15 pounds

It is outside the healthy weight range and is in the top 5% of weights of cats.

Gordo's weight makes the cat unhealthy.

Flaco's weight = 8 pounds

Flaco's weight lies in the healthy weight range for cats. Hence, Flaco is a healthy cat.

8 0
2 years ago
Can you tell i'm panicking? ^^"
Archy [21]
ANSWER:
The right option is d)
As 5*1=5
5*3=15
5*4=20

HOPE IT HELPS!!!!!
PLEASE MARK BRAINLIEST!!!!
4 0
3 years ago
Can you please explain to me what the end behavior of the function f(x)=-2x^4-x^3+3 looks like?
Artist 52 [7]
The dominant term is -2x⁴. 

As X approaches infinite, y is naturally going to be really large as well.

Remember that a number with an even exponent, regardless of whether it's positive or negative, will be positive.
As x approaches infinite, y will approach -2 * ∞, or -∞. Therefore, the end behavior in the positive direction is y=-∞
As x approaches negative infinite, y will approach -2 *∞ again. This is because         -∞⁴ = ∞. Therefore, the end behavior in the negative direction is also y=-∞

Basically, due to the dominance of the -2x^4 term, the function will look more or less like a downward facing parabola with a y-intercept of 3.
7 0
3 years ago
I need help with INTERIM CHECKPOINT problem
morpeh [17]
The answer is d I think.
6 0
3 years ago
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