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sweet [91]
2 years ago
14

What is the answer to 25% of 50

Mathematics
1 answer:
a_sh-v [17]2 years ago
8 0

Answer:

12.5

Step-by-step explanation:

.25 x 50= 12.5

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Write and solve an equation to find the unknown angle.
Julli [10]
There's many properties you can use to find an unknown angle.

There are too many to lists but one core example would be an isosceles triangle that has two adjacent sides and angles.

Let's say that the sides of an isosceles triangle are any number "x"

now since two sides of the triangle are the same we can add these two x's together.

x+x = 2x

now the other side of the triangle can be anything you like. We can call it 4x for this example.

now if we add them all together we'll get 4x+2x=6x

Now since the angles of a triangle add up to 180 degrees
we can equate 6x=180 leaving x to be 30.

Now since x belongs to both sides of the triangle we can say that both angles are congruent as well because the two sides of the triangle are congruent. This is a known triangle law.

Since both angles are now 30 degrees this will leave us with 2(30) = 60

now if we subtract 180 - 60 we'll get 120 which is the remainder of the 3rd angle of the side that corresponds with 4x.
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5 0
4 years ago
Helppppp giving brainly too ​
sweet [91]
Alright. (1/4^2)+2((1/4)(2/3)-3(2/3^2)=-.9375 is the correct answer
4 0
3 years ago
Read 2 more answers
#17-1: Simplify this complex fraction. 1/3 / 6/9
Gnesinka [82]

\huge{\boxed{\frac{1}{2}}}

To divide by a fraction, you multiply by its reciprocal, which you find by flipping the numerator and the denominator. \frac{1}{3} \div \frac{6}{9} = \frac{1}{3} * \frac{9}{6}

Multiply the numerators and the denominators separately. \frac{1}{3} * \frac{9}{6} = \frac{1*9}{3*6} = \frac{9}{18}

Simplify by dividing both sides of the equation by 9. \frac{9 \div 9}{18 \div 9} = \boxed{\frac{1}{2}}

3 0
3 years ago
Read 2 more answers
Determine whether
lora16 [44]

Answer:

(a) and (b) are not equivalent

(c) is equivalent

Step-by-step explanation:

Given

\frac{25^m}{5}

Required

Determine an equivalent or nonequivalent expression

(a)\ 25^{m-1

We have:

25^{m-1

Apply law of indices

25^{m-1} = \frac{25^m}{25}

<em>This is not equivalent to </em>\frac{25^m}{5}<em></em>

(b)\ 25^{2m - 1}

We have:

25^{2m - 1}

Apply law of indices

25^{2m - 1} = \frac{25^{2m}}{25}

<em>This is not equivalent to </em>\frac{25^m}{5}<em></em>

<em></em>

<em />(c)\ 5^{2m-1}<em />

We have:

<em />5^{2m-1}<em />

Apply law of indices

<em />5^{2m-1} = \frac{5^{2m}}{5^1}<em />

<em />5^{2m-1} = \frac{5^{2m}}{5}<em />

<em>Evaluate the numerator</em>

<em />5^{2m-1} = \frac{25m}{5}<em />

<em />

<em>This is an equivalent expression</em>

4 0
3 years ago
Solve the following equation algebraically: x^2=20
Zielflug [23.3K]

Answer:

x = ± 2\sqrt{5}

Step-by-step explanation:

Given

x² = 20 ( take the square root of both sides )

x = ± \sqrt{20} = ± \sqrt{4(5)} = ± 2\sqrt{5}

6 0
3 years ago
Read 2 more answers
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