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Rasek [7]
3 years ago
15

Solve the following equation algebraically: x^2=20

Mathematics
2 answers:
amid [387]3 years ago
8 0

Answer:

Step-by-step explanation:

x² = 20

x² - 20 = 0

x² -  (√20)² =0

by identity : a² - b² =  ( a - b )( a + b) in this exercice : a = x and b =√20

( x - √20)(x + √20) = 0

x - √20 = 0  or  x + √20 = 0

x = √20 or x =  - √20

but : 20 = 4×5

20 = √(4×5) =√4×√5 = 2√5

Zielflug [23.3K]3 years ago
6 0

Answer:

x = ± 2\sqrt{5}

Step-by-step explanation:

Given

x² = 20 ( take the square root of both sides )

x = ± \sqrt{20} = ± \sqrt{4(5)} = ± 2\sqrt{5}

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