Answer:
Written in Python
for num in range(1,1001):
sum=0
for j in range(1,num+1):
if num%j==0:
sum = sum + j
if num == sum:
print(str(num)+" is a perfect number")
Explanation:
This line gets the range from 1 to 1000
for num in range(1,1001):
This line initializes sum to 0 for each number 1 to 1000
sum=0
This line gets the divisor for each number 1 to 1000
for j in range(1,num+1):
This following if condition line checks for divisor of each number
<em> if num%j==0:
</em>
<em> sum = sum + j
</em>
The following if condition checks for perfect number
if num == sum:
print(str(num)+" is a perfect number")
Answer:
Print 4 + 4
Explanation:
If you're writing this in the programming language called BASIC, this is how you would add any two numbers.
Sorry but your notation is ambiguous
Is it U(n+1) = (3U(n) + 1)/(5U(n) + 3)
or U(n+1) = (3U(n) + 1)/(5U(n)) + 3
or U(n+1) = 3U(n) + (1/5U(n)) + 3
or U(n+1) = 3U(n) + (1/5)U(n) + 3?
<span>If so, what do you wish us to do with this sequence?
I hope my answer has come to your help. Thank you for posting your question here in Brainly. We hope to answer more of your questions and inquiries soon. Have a nice day ahead!
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True, and there are many other web browsers
