Answer:
Given code output is "786".
Explanation:
Code:
list1 = [ 'cyber', 786 , 2.23, 'square', 70.2 ]#defining a list list1 that holds value in parameter
print (list1[1] )#use a print method that prints list index value
In the given code a list "list1" is declared that holds value in it and in the next step a print method is declared that prints the first index value of the list.
Answer:
Explanation:
The following Python program uses a combination of dictionary, list, regex, and loops to accomplish what was requested. The function takes a file name as input, reads the file, and saves the individual words in a list. Then it loops through the list, adding each word into a dictionary with the number of times it appears. If the word is already in the dictionary it adds 1 to its count value. The program was tested with a file named great_expectations.txt and the output can be seen below.
import re
def wordCount(fileName):
file = open(fileName, 'r')
wordList = file.read().lower()
wordList = re.split('\s', wordList)
wordDict = {}
for word in wordList:
if word in wordDict:
wordDict[word] = wordDict.get(word) + 1
else:
wordDict[word] = 1
print(wordDict)
wordCount('great_expectations.txt')
