Answer: 0.965
Step-by-step explanation:
Given : Water use in the summer is normally distributed with
Let X be the random variable that represents the quantity of water required on a particular day.
Z-score : 
Now, the probability that a day requires more water than is stored in city reservoirs is given by:-
We can see that on comparing the above value to the given P(X > 350)= 1 - P(Z < b) , we get the value of b is 0.965.
Answer:
The number of times members and non-members will have to rent a boat in order to pay the same amount=20
Step-by-step explanation:
We can have two expressions to show the total cost paid by a member and non-member;
Total cost by member=Cost per summer season+cost per number of times they rent a boat×number of times they rent a boat
where;
Cost per summer season=$105
Cost per number of times they rent a boat=$9.50
Number of times they rent a boat=n
Replacing;
Total cost by a member=105+(9.5×n)=9.5 n+105......equation 1
Total cost by a non-member=Cost per number of times they rent a boat×number of times they rent a boat
where;
Cost per number of times they rent a boat=$14.75
Number of times they rent a boat=n
Replacing;
Total cost by a non-member=(14.75×n)=14.75 n......equation 2
To calculate the number of times they would have to rent a boat in order to pay the same amount, we equate equation 1 to equation 2
9.5 n+105=14.75 n
14.75 n-9.5 n=105
5.25 n=105
n=105/5.25
n=20
The number of times members and non-members will have to rent a boat in order to pay the same amount=20
Answer:
(C) 220
Step-by-step explanation:
Let x represent the number of adult tickets sold and y represent the number of student tickets sold. With the information given, we can set up two equations:
(Since for every adult ticket sold, $5 is made and for every student ticket sold, $3 is made)
In the first equation, we can represent x in terms of y:
And then, we can substitute x in the second equation for 360 - y to get:
which simplifies to:
and therefore, 
.
Hope this helps :)
a+b+c=0
[(a+b+c)^2=a^2+b^2+c^2+2ab+2ac+2bc]
[a^2+b^2+c^2+2ab+2ac+2bc=0]
[a^2+b^2+c^2=-(2ab+2ac+2bc)]
[a^2+b^2+c^2=-2(ab+ac+bc)] (i)
also
[a=-b-c]
[a^2=-ab-ac] (ii)
[-c=a+b]
[-bc=ab+b^2] (iii)
adding (ii) and (iii) ,we have
[a^2-bc=b^2-ac] (iv)
devide (i) by (iv)
[(a^2+b^2+c^2)/(a^2-bc)=(-2(ab+bc+ca))/(b^2-ac)]
Answer: 4 por 8
Step-by-step explanation:
