Need help with number 2
1 answer:
You might be interested in
Answer:
Step-by-step explanation:
A hyperbola is the locus of a point such that its distance from a point to two points (known as foci) is a positive constant.
The standard equation of a hyperbola centered at the origin with transverse on the x axis is given as:
The coordinates of the foci is at (±c, 0), where c² = a² + b²
Given that a hyperbola centered at the origin with x-intercepts +/- 4 and foci of +/-2√5. Since the x intercept is ±4, this means that at y = 0, x = 4. Substituting in the standard equation:
I don't feel like explaining so...
a. = 4
The foci c is at +/-2√5, using c² = a² + b²:
B = 2
Substituting the value of a and b to get the equation of the hyperbola:
<h3>Answer:</h3>
Factor 6 from the first two terms.
<h3>Step-by-step explanation:</h3>By factoring out "a", you can better see what "h" needs to be.
- y = 6(x^2 +3x) +14 . . . . 6 factored from first 2 terms
- add the square of half the x-coefficient inside parentheses; add the opposite outside: y = 6(x^2 +3x +2.25) +14 -6(2.25)
- rewrite as a square; combine the constants: y = 6(x+1.5)^2 +0.5