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Rudik [331]
3 years ago
11

Line segment XY begins at (-6,4) and ends at (-2,4). The segment is reflected over the x-axis and translated left 3 units to for

m line segment X'Y'. Enter the lenght, in units, of line segment X'Y'
Mathematics
1 answer:
hoa [83]3 years ago
3 0

Line segment XY begins at (-6,4) and ends at (-2,4); XY is reflected over the x-axis and translated left 3 units to form line segment X'Y' which has a length of 4 units.

<h3>What is an equation?</h3>

An equation is an expression that shows the relationship between two or more numbers and variables.

Line segment XY begins at (-6,4) and ends at (-2,4). Hence:

XY=\sqrt{(4-4)^2+(-2-(-6))^2}=4\ units

XY is reflected over the x-axis and translated left 3 units to form line segment X'Y'. Hence:

XY = X'Y' = 4 units

Line segment XY begins at (-6,4) and ends at (-2,4); XY is reflected over the x-axis and translated left 3 units to form line segment X'Y' which has a length of 4 units.

Find out more on equation at: brainly.com/question/2972832

#SPJ1

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