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kherson [118]
4 years ago
10

Explain how to write 2.14 x 10 to the negative power of 5 in standard form by moving the decimal point

Mathematics
2 answers:
Hatshy [7]4 years ago
7 0

Answer:

21.4 * 10^(-5)

Step-by-step explanation:

bezimeni [28]4 years ago
5 0

Step-by-step explanation:

just learned it this year move the decimal point to left to make a negative number

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2/ 3 (6 − 9x) = 16. Can someone pls help me
lidiya [134]

Answer:

-2 is your answer

Step-by-step explanation:

First, you get 2/3 and distribute it into the parentheses that gives you

4-6x=16

now you subtract 4 on both sides leaving you with

-6/-6 which cancels out you have

12/-6 whigh is -2 and that is your answer

8 0
3 years ago
Is the following relation a function?
abruzzese [7]

Answer:

Yes bc the x is not repeating

Step-by-step explanation: Remember if the domain(x) is repeating like (4,4) (4,3) it is not a function because of the x and don't worrying about the y (range)  and if the domain is not repeating like (2,3)(3,8) it is a function bc of the domain (x) hope this help:)

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3 years ago
The local public transport authority is conducting research into commuter behaviour. A previous census indicated that the mean c
kondor19780726 [428]

Answer:

H_0:\mu  = 45 and H_a:\mu  < 45

T = 34.88

The null hypothesis is not rejected

Step-by-step explanation:

Given

Random sample of 50 commuter times

Solving (a): The null and alternate hypothesis

From the question, a previous census shows that:

\mu =45 and \sigma= 9.1

This is the null hypothesis i.e.

H_0:\mu  = 45

Reading further, a new test was to show whether the average has decreased.

This is the alternate hypothesis, and it is represented as:

H_a:\mu  < 45

Solving (b) and (c): The test statistic (T).

This is calculated using:

T = \frac{\mu}{\sigma/\sqrt n}

In this case:

n = 50   \mu =45 and \sigma= 9.1

So:

T = \frac{45}{9.1/\sqrt{50}}

T = \frac{45}{9.1/7.07}

T = \frac{45}{1.29}

T = 34.88

Solving (c): Accept or reject null hypothesis

\alpha = 0.05

First calculate the degrees of freedom (df)

df = n - 1 = 50 - 1

d f = 49

From the t distribution table,

At: d f = 49,  \alpha = 0.05 and T = 34.88

the t score is:

p = 1.676

p > 0.05

<em>So, the null hypothesis is not rejected</em>

7 0
3 years ago
Find the slope of the line that passes through the points (-1,8) and (3, -4). Is this slope greater than, less than, or equal to
Gre4nikov [31]
Slope is -3 and it is less than the slope of y=3x+5
4 0
3 years ago
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