Question

Students reported practicing violin during the last semester for 45, 38, 52, 58, and 42 hours. What is the mean absolute deviation for the number of hours students practiced the violin? Round to the nearest tenth. 6. 4 6. 8 32 47.

Answer 1

The mean absolute deviation for the number of hours students practiced the violin is 6.4.

What is the mean absolute deviation?

The average absolute deviation of the collected data set is the average of absolute deviations from a center point of the data set.

Given

Students reported practicing violin during the last semester for 45, 38, 52, 58, and 42 hours.

The given data set is;

45, 38, 52, 58, 42

Mean Deviation = Σ|x − μ|/N.

μ = mean, and N = total number of values

|x − μ| = |45 − 47| = 2

|38− 47| = 9

|52− 47| = 5

|58− 47| = 11

|42− 47| = 5

The mean absolute deviation for the number of hours students practiced the violin is;

$\rm Mean =\dfrac{2+9+5+11+5}{5}\\\\Mean=\dfrac{32}{5}\\\\Mean = 6.4$

Hence, the mean absolute deviation for the number of hours students practiced the violin is 6.4.

To know more about mean value click the link given below.

brainly.com/question/5003198