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Cloud [144]
2 years ago
9

Work out

absmiddle" class="latex-formula"> of 80
Mathematics
2 answers:
NNADVOKAT [17]2 years ago
7 0

Answer:

Here we will explain how to calculate one half of 80.

One half of 80 is simply one half times 80, which can be written as follows:

One/half x 80

Furthermore, you can convert "one" to "1" and "half" to "2" and then the equation and answer is:

1/2 x 80 = 40.00

Step-by-step explanation:

oee [108]2 years ago
5 0

Hey there!

In order to find 1/5 of 80, we can just multiply 80 times 1/5:

\bold{\displaystyle\frac{1}{5} *80}

80 can be written as follows:

\bold{\displaystyle\frac{1}{5} *\frac{80}{1}}

In order to multiply fractions, just multiply the top of one fraction times the top of the other fraction; same with the bottom (also called the denominator)

\bold{\displaystyle\frac{80}{5}}

Guess what? Now we can use mental maths to solve it :)

Hence, the answer is

\boxed{\boxed{\bold{16}}}

Hope everything is clear.

Let me know if you have any questions!

#ILoveLearning

:-)

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Can someone solve this? The answer needs to be in fraction form so can't be done by a calculator.
Lesechka [4]

Answer:

9 1/6

You may use a fraction calulator for this question by the way!

Hope this helps!

Sorry if its wrong!

Have a nice day!

7 0
3 years ago
When translating the phrase "twice the quantity of four more than three times a number"on students wrote the expression 2*3x+4
kozerog [31]
It is wrong because the equation is missing parentheses around the sum

When it says "the quantity of..." it always means parentheses. The correct equation is 2(3x+4)
5 0
3 years ago
Solve the for the inequality ​
Naddika [18.5K]

Answer:

k ≥ -18

Step-by-step explanation:

-8\leq \frac{2}{5}(k-2)\\\\-8(5)\leq (5)\frac{2}{5}(k-2)\\\\-40\leq 2(k-2)\\\\\frac{-40}{2}\leq \frac{2(k-2)}{2}\\\\-20\leq k-2\\\\-20+2\leq k-2+2\\\\-18\leq k

5 0
3 years ago
Read 2 more answers
A survey of 2500 subscribers to a certain news paper revealed that 2250 people subscribe to the daily morning edition and 1250 s
Aleks04 [339]

1500 people subscribed Sunday edition and 250 people subscribed only sunday edition.

<u>Solution:</u>

Given, A survey of 2500 subscribers to a certain news paper revealed that 2250 people subscribe to the daily morning edition  

And 1250 subscribe to both the daily and the sunday editions.  

We have to find how many subscribe to the Sunday edition? how many subscribe to the Sunday edition only?

Let x denote the number who subscribe to the Sunday edition.  

Then the addition rule with overlap tells us that  

Those who subscribe daily edition + those who subscribe sunday edition - those who subscribe both daily and sunday edition = total subscribers in survey

2250 + x – 1250 = 2500

1000 + x = 2500  

x = 1500  

so, 1500 subscribe to the Sunday edition and 1500 – 1250 = 250 subscribe to the Sunday edition only.

Hence, 1500 people subscribed Sunday edition and 250 people subscribed only sunday edition.

6 0
3 years ago
In a certain town, the amount of sulfur oxide in the air, S, in tons, is related to the town’s population, P, in people. The rel
Lady bird [3.3K]

Answer:

Change in sulfur oxide in the air = \frac{\textup{110010}}{\textup{S}}

Step-by-step explanation:

Data provided in the question:

Relation between the amount of sulfur oxide in the air and the population as:

S² = 110P² + 20P + 600

Population growth rate, \frac{\textup{dP}}{\textup{dt}}  = 10 people per month

Now,

change in sulfur oxide with time i.e \frac{\textup{dS}}{\textup{dt}}

differentiating the given relation with respect to time 't'

we have

2S\frac{\textup{dS}}{\textup{dt}} =  2\times110P\frac{\textup{dP}}{\textup{dt}}  + 20

at P = 100 and  \frac{\textup{dP}}{\textup{dt}}  = 10 people per month

we have

2S\frac{\textup{dS}}{\textup{dt}} = 2 × 110 × 100 × 10 + 20

or

2S\frac{\textup{dS}}{\textup{dt}} = 220020

or

\frac{\textup{dS}}{\textup{dt}} = \frac{\textup{220020}}{\textup{2S}}

or

Change in sulfur oxide in the air = \frac{\textup{110010}}{\textup{S}}

8 0
2 years ago
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