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grandymaker [24]
4 years ago
12

Find the quotient 7/9 divided by 5/6

Mathematics
1 answer:
Blizzard [7]4 years ago
3 0
7/9 divided by 5/6 = 14/15
in decimal for it would be 0.93
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Select the correct answer
Sidana [21]

Answer:

<em>In simplest form, 75% gives 3/4 as a fraction. </em>

<em>The percent sign means divide by 100, so 75% means 75/100.</em>

3 0
3 years ago
Which experession is equivalent to
Readme [11.4K]

Hey there!

8x + 4y - 2x + 6y - 3
COMBINE the LIKE TERMS

= (8x - 2x) + (4y + 6y) - (3)

= 8x - 2x + 4y + 6y - 3

= 6x + 10y - 3


Therefore, your answer is:

6x + 10y - 3 (Optipn A.)


Good luck on your assignment & enjoy your day!



~Amphitrite1040:)

7 0
2 years ago
Read 2 more answers
I need help with this two questions.
mezya [45]
Always get rid of denominators first. Multiply both right and left side by 6
-7 (6) = -c (6)/6 + 12(6)
-42 = -c + 72
c = 72 +42
c = 114

rearrange like terms together
42 = 18 - 4x
4x = 18 -42
4x = -24
divide both sides by 4
x = -6
8 0
3 years ago
Please help asap thanks so much
zvonat [6]

Complementary and adjacent.

The two angles are complementary because they add up to 90°. It's given that line JL is perpendicular to line MN, and perpendicular means they form a 90° angle where they intersect.

The two angles are adjacent because they are next to each other.

8 0
3 years ago
Part A. Write an equation of a line that is perpendicular to the line y = 2/3x + 5 and passes through the point (4, 0).
fenix001 [56]

Answer:

y = -\frac{3}{2}x+6

Step-by-step explanation:

Given:

The given equation of the line y = \frac{2}{3} x + 5 that passes through the point (4, 0).

Part A.

The equation of the line.

y=mx+c-----------(1)

Where:

m = Slope of the line

c = y-intercept

The given equation of the line.

y = \frac{2}{3} x + 5

Comparing the given equation with equation 1.

The slope of the line is m=\frac{2}{3} and y-intercept c = 5

We know that the slope of the perpendicular line is (-\frac{1}{m}).

So the slope of the perpendicular line is (m=-\frac{1}{\frac{2}{3}}=-\frac{3}{2}).

Using point slope formula we write the equation of the perpendicular line that passes through the point (4, 0).

y-y_{1} = m(x-x_{1}

Now we substitute the slope of the perpendicular line m=-\frac{3}{2} and y_{1} = 0, x_{1}=4 from point (4, 0) in above equation.  

y-0 = -\frac{3}{2}(x-4)

y = -\frac{3}{2}x-(-\frac{3}{2}\times 4)

y = -\frac{3}{2}x-(-3\times 2)

y = -\frac{3}{2}x-(-6)

y = -\frac{3}{2}x+6

Therefore the perpendicular line equation is y = -\frac{3}{2}x+6.

Part B.

1. The slope of the perpendicular line is m=-\frac{3}{2}.

2. The y-intercept of the perpendicular line is 6.

3. The equation of the line y = -\frac{3}{2}x+6 is perpendicular to the equation of line y = \frac{2}{3} x + 5.

6 0
3 years ago
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