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Ostrovityanka [42]
3 years ago
9

One number is 8 more than another. If the sum of the smaller number and twice the larger number is 46, find the two numbers.Let

x = the first number
Mathematics
1 answer:
valkas [14]3 years ago
3 0

Answer:

x = 18 y = 10

Step-by-step explanation:

let the first number be x

let the second number be y

x = y + 8..... equation 1

2x + y = 46.... equation 2

x is the larger number

y is the smaller number.

Rearrange the equation and add equation 1 to equation 2.

x - y = 8

+ 2x + y = 46

-------------------

3x + 0 = 54

3x = 54

divide both sides by 3

x = 54/3

x = 18

Substitute x = 18 into equation 1

x = y + 8

18 = y + 8

collect like terms

y = 18-8

y = 10

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Drupady [299]

Answer: hello your question is incomplete attached below is the missing codes

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Step-by-step explanation:

It may not work because; the double pointer P was not allotted a double using a new double ( I.e. Error in the main function ) also the cout statement  should be moved to the Main

<u><em>The correction  is below </em></u>

{

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7 0
3 years ago
Given:quadrillateral ABCD inscribed in a circle
son4ous [18]

Answer:

Step-by-step explanation:

Given: quadrilateral ABCD inscribed in a circle

To Prove:

1. ∠A and ∠C are supplementary.

2. ∠B and ∠D are supplementary.

Construction : Join AC and BD.

Proof: As, angle in same segment of circle are equal.Considering AB, BC, CD and DA as Segments, which are inside the circle,

∠1=∠2-----(1)

∠3=∠4-----(2)

∠5=∠6-------(3)

∠7=∠8------(4)

Also, sum of angles of quadrilateral is 360°.

⇒∠A+∠B+∠C+∠D=360°

→→∠1+∠2+∠3+∠4+∠5+∠6+∠7+∠8=360°→→→using 1,2,3,and 4

→→→2∠1+2∠4+2∠6+2∠8=360°

→→→→2( ∠1 +∠6) +2(∠4+∠8)=360°⇒Dividing both sides by 2,

→→→∠B + ∠D=180°as, ∠1 +∠6=∠B , ∠4+∠8=∠B------(A)

As, ∠A+∠B+∠C+∠D=360°

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∠A+∠C=180°

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credit: someone else

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3 years ago
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Likurg_2 [28]
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3 years ago
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Anton [14]

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a_sh-v [17]

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4 0
3 years ago
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