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Ostrovityanka [42]
3 years ago
9

One number is 8 more than another. If the sum of the smaller number and twice the larger number is 46, find the two numbers.Let

x = the first number
Mathematics
1 answer:
valkas [14]3 years ago
3 0

Answer:

x = 18 y = 10

Step-by-step explanation:

let the first number be x

let the second number be y

x = y + 8..... equation 1

2x + y = 46.... equation 2

x is the larger number

y is the smaller number.

Rearrange the equation and add equation 1 to equation 2.

x - y = 8

+ 2x + y = 46

-------------------

3x + 0 = 54

3x = 54

divide both sides by 3

x = 54/3

x = 18

Substitute x = 18 into equation 1

x = y + 8

18 = y + 8

collect like terms

y = 18-8

y = 10

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