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2 years ago

7

A shoe box is covered with packing paper before being shipped. The paper costs $0.02 per square inch. How much will it cost to c

over three shoe boxes?

1 answer:

dimulka [17.4K]2 years ago

3 0

The cost of the money is 8 dollars and then you owe me money to get your free shipping

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For the following reports about statistical studies, identify the following items (if possible). If you can't tell, then say so-

Ira Lisetskai [31]

Answer:

Population: Soil around a former waste dump
Parameter: Concentrations of toxic chemicals
Sample frame: Accessible soil around dump
Sample: 16 soil samples
Method: Unclear
Bias: Uncertain if soil samples were randomly chosen

Step-by-step explanation:

The above answer explanation can be more clear by understanding that the population is the soil around the former waste dump and the samples are 16 which were taken from EPA.In report, the method is unclear too.

5 0

3 years ago

A rectangle has length 12 feet and width 8 feet. Every dimension of the rectangle is multiplied by 3/4 to form a similar rectang

kap26 [50]

Let the area of the original rectangle be A₁.

A₁ = (12 ft)(8 feet) = 96 ft²

To determine the area of the reduced triangle, let's compute the new dimensions first.

Length = 12 ft * 3/4 - 9 ft
Width = 8 ft *3/4 = 6 ft

Thus, the area of the new rectangle denoted as A₂ is
A₂ = (9 ft)(6 ft) = 54 ft

The ratio of the areas are:
A₂/A₁ = 54/96 = 9/16
The ratio of the sides are given to be 3/4.
Finally the ratios of the area to side would be:
Ratio = 9/16 ÷ 3/4 = 3/4

Therefore, the ratio of the areas is 3/4 of the ratio of the corresponding sides.

8 0

3 years ago

180kg, 250kg, 200kg, 209kg, 195kg, 205kg, 190kg, 188kg, 192kg. What is the IQR of the lion's weights.

velikii [3]

Answer:

18

Step-by-step explanation:

Given the data:

180kg, 250kg, 200kg, 209kg, 195kg, 205kg, 190kg, 188kg, 192kg

The interquartile range (IQR) = Q3 - Q1

Reordering the data:

180, 188, 190, 192, 195, 200, 205, 209, 250

Q3 = 3/4(n+1)th term

Q3 = 3/4(10) = 7.5 th term = (205+209)/2 = 207

Q1 = 1/4(n+1)th term

Q1 = 1/4(10) = 2.5th term = (188+190)/2 = 189

Q3 - Q1 = 207 - 189 = 18

3 0

3 years ago

PLEASE SOLVE THIS FOR ME ITS DUE TOMORROW <br><br>Find an expression for the missing dimension.

denis-greek [22]

Answer:

The missing length is 2x+5

Step-by-step explanation:

Given equation of volume of cuboid is V= $2x^{3} +17x^{2} +46x+40$

Figure show that

Length of cuboid is ?

Width of cuboid is (x+4)

Height of cuboid is (x+2)

The volume of cuboid is given by

V=Length x Width x Height

Let Length be (bx+a)

The volume of cuboid will be

$V=(bx+a)(x+4)(x+2)$

$V=(bx+a)[x^{2}+4x+2x+8 ]$

$V=bx[x^{2}+6x+8]+a[x^{2}+6x+8]$

$V=[bx^{3}+6bx^{2}+8bx]+[ax^{2}+6ax+8a]$

$V=[bx^{3}+(6b+a)x^{2}+(8b+6a)x+8a]$

On comparing coefficient with given equation of volume

We get,

b=2 and 8a=40

Therefore, the value of a is 5 and b is 2

Thus, The missing length is bx+a=2x+5

7 0

3 years ago

Solve for y<br>7y + 9 - 10y = -18<br>What is y simplify your answer as much as possible.

Tpy6a [65]

Y = 9

7y - 10y = -3y
bring down the 9 = -18 so

-3y + 9 = -18

9 - 9 = 0
- 18 - 9 = - 27

- 3y ÷ - 3 = y
- 27 ÷ -3 = 9

therefore y =9

7 0

3 years ago