Question

NEED PRE CALC HELP WILL GIVE BRAINLIEST

Answer 1

• Solutions for a system of equations means finding out common points for the equations.

• ( look attached file screenshot from Geogebra)

The solution is:

Point P ( -2 ; 0)

Point Q ( 1 ; -6)

2) If the linear equation never touches the quadratic function the system has no solution

The system:

2×x + y = -4           or    y = -4 - 2×x

y = x² - x - 6    (1)

Solving ( by substitution of  y value in equation (1)  )

- 4 - 2× x  =  x² - x - 6

x² - x - 6 + 4 + 2×x = 0

x² + x -2 = 0

Solving for x

x₁,₂ = ( - 1 ± √1 +8 ) / 2

x₁,₂ =  (-1 ± 3 )/2

x₁ = - 2

x₂ =  1

Now for x₁ = -2            y = (-2)² - ( -2) - 6     y =  0

Point P ( -2 ; 0)

For  x₂ = 1                    y = (1)² - ( 1) - 6          y = - 6

Point Q ( 1 ; -6)

Related Links: brainly.com/question/19130975