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3 years ago

A line is parallel to the y-axis on a coordinate plane. Which best describes the slope of the line

Mathematics

2 answers:

kodGreya [7K]3 years ago

6 0

Answer:

well if it is parallel it would but 2 lines going in the same direction. it will never touch

Step-by-step explanation:

Katena32 [7]3 years ago

5 0

Answer:

The slope of this line is undefined.

Explanation:

The slope of a line is rise over run, where the rise is the change in y value and the run is the change in x. Since there is no change in x when a line is parallel to the y-axis, any slope would mean you would divide by 0.

$m=\frac{rise}{run}\\m = \frac{rise}{0} \\m= \frac{anything}{0}\\$

Since you cannot divide by 0 the answer will always be undefined no matter what the numerator is. The slope of any vertical line will be undefined.

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Write an equation of a line with the given slope and y-intercept. m = –5, b = –3. A. y = –5x – 3 . B. y = –5x + 3 . C. y = 5x –

True [87]

Y = mx + b
y = -5x -3

5 0

3 years ago

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What is the probability of spinning a C? В В A В [?]% СА СС

Mkey [24]

3/8 * 100 = 37.5%
To an integer it is 38%

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3 years ago

The ratio for 42 pens : 35 pencils as a fraction is

Lynna [10]

42:35 or if simplified 6:5

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4 years ago

A piece of paper is to display ~128~ 128 space, 128, space square inches of text. If there are to be one-inch margins on both si

Grace [21]

Answer:

The dimensions of the smallest piece that can be used are: 10 by 20 and the area is 200 square inches

Step-by-step explanation:

We have that:

$Area = 128$

Let the dimension of the paper be x and y;

Such that:

$Length = x$

$Width = y$

So:

$Area = x * y$

Substitute 128 for Area

$128 = x * y$

Make x the subject

$x = \frac{128}{y}$

When 1 inch margin is at top and bottom

The length becomes:

$Length = x + 1 + 1$

$Length = x + 2$

When 2 inch margin is at both sides

The width becomes:

$Width = y + 2 + 2$

$Width = y + 4$

The New Area (A) is then calculated as:

$A = (x + 2) * (y + 4)$

Substitute $\frac{128}{y}$ for x

$A = (\frac{128}{y} + 2) * (y + 4)$

Open Brackets

$A = 128 + \frac{512}{y} + 2y + 8$

Collect Like Terms

$A = \frac{512}{y} + 2y + 8+128$

$A = \frac{512}{y} + 2y + 136$

$A= 512y^{-1} + 2y + 136$

To calculate the smallest possible value of y, we have to apply calculus.

Different A with respect to y

$A' = -512y^{-2} + 2$

Set

$A' = 0$

This gives:

$0 = -512y^{-2} + 2$

Collect Like Terms

$512y^{-2} = 2$

Multiply through by $y^2$

$y^2 * 512y^{-2} = 2 * y^2$

$512 = 2y^2$

Divide through by 2

$256=y^2$

Take square roots of both sides

$\sqrt{256=y^2$

$16=y$

$y = 16$

Recall that:

$x = \frac{128}{y}$

$x = \frac{128}{16}$

$x = 8$

Recall that the new dimensions are:

$Length = x + 2$

$Width = y + 4$

So:

$Length = 8 + 2$

$Length = 10$

$Width = 16 + 4$

$Width = 20$

To double-check;

Differentiate A'

$A' = -512y^{-2} + 2$

$A" = -2 * -512y^{-3}$

$A" = 1024y^{-3}$

$A" = \frac{1024}{y^3}$

The above value is:

$A" = \frac{1024}{y^3} > 0$

This means that the calculated values are at minimum.

Hence, the dimensions of the smallest piece that can be used are: 10 by 20 and the area is 200 square inches

3 0

3 years ago

Two parallel lines are crossed by a transversal. Horizontal and parallel lines p and q are cut by transversal m. At the intersec

egoroff_w [7]

Answer:

If two parallel lines are cut by a transversal, then the pairs of consecutive interior angles formed are supplementary . ... When two lines are cut by a transversal, the pairs of angles on either side of the transversal and outside the two lines are called the alternate exterior angles .

Step-by-step explanation:

hope this helps you :)

6 0

3 years ago

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