All categories

2 years ago

Please please please help!!!

Mathematics

1 answer:

dalvyx [7]2 years ago

7 0

9514 1404 393

Answer:

Step-by-step explanation:

Fill in the argument value and look up the function value on the graph.

$(f\circ f)(-2) = f(f(-2)) = f(2) = \boxed{2}$

You might be interested in

35x+10. How do I solve this?

kicyunya [14]

Hey there Bfarrar07 !

This is pretty simple when you think about it.

With algebra problems like this, you want to set it equal to zero.

So your first step is to take 35x + 10 and set it equal to zero.

35x + 10 = 0

Then bring the 10 to the other side by subtracting it, so you have something like this:

35x + 10 (-10) = -10 (Remember, what you do to one side you have to do to the other!) So when you take 10 from the left, you have to take ten from the right.

You now have 35x = -10

In order to get x by itself, you need to divide the problem by 35.

35x/35 = -10/35

On the left hand side, the 35's cancel out, so you're left with x.

And on the right hand side you have -10/35

So x = -10/35 (Don't forget to simplify!)

-10/35 can be reduced to -5/7

X = - 5/7

Hope this helps!

3 0

4 years ago

Solve the system of equations and choose the correct answer from the list of options.

Georgia [21]

We can solve this system of equation by reduction method.
  d+e=15
-d+e=-5
-------------------
2e=10   ⇒e=10/2=5

-(d+e=15)
-d+e=-5
-----------------
-2d=-20   ⇒d=-20/-2=10

therefore: d=10; e=5

Answer: d.(10,5)

8 0

3 years ago

A ball is launched upward at 14 m/s from a platform 30 m high.Find the maximum height the ball will reach and how long it will t

BartSMP [9]

Answer:

The ball will reach a maximum height of 39.993 meters after 1.428 seconds.

Step-by-step explanation:

Let suppose that no non-conservative forces acts on the ball during its motion, then we can determine the maximum height reached by the Principle of Energy Conservation, which states that:

$K_{1}+U_{g,1} = K_{2}+U_{g,2}$ (1)

Where:

$K_{1}$ , $K_{2}$ - Initial and final translational kinetic energies, measured in joules.

$U_{g,1}$ , $U_{g,2}$ - Initial and final gravitational potential energies, measured in joules.

By definition of translational kinetic energy and gravitational potential energy we expand and simplify the expression above:

$\frac{1}{2}\cdot m\cdot v_{2}^{2}+m\cdot g\cdot y_{2}= \frac{1}{2}\cdot m\cdot v_{1}^{2}+m\cdot g\cdot y_{1}$ (2)

Where:

$m$ - Mass of the ball, measured in kilograms.

$g$ - Gravitational acceleration, measured in meters per square second.

$v_{1}$ , $v_{2}$ - Initial and final speed of the ball, measured in meters per second.

$y_{1}$ , $y_{2}$ - Initial and final heights of the ball, measured in meters.

The final height of the ball is determined by the following formula:

$v_{2}^{2}+2\cdot g\cdot y_{2} = v_{1}^{2}+2\cdot g\cdot y_{1}$

$v_{1}^{2}-v_{2}^{2}+2\cdot g \cdot y_{1}=2\cdot g\cdot y_{2}$

$y_{2} = y_{1}+\frac{v_{1}^{2}-v_{2}^{2}}{2\cdot g}$ (3)

If we know that $y_{1} = 30\,m$ , $v_{1} = 14\,\frac{m}{s}$ , $v_{2} = 0\,\frac{m}{s}$ and $g = 9.807\,\frac{m}{s^{2}}$ , the maximum height that the ball will reach is:

$y_{2} = 30\,m + \frac{\left(14\,\frac{m}{s} \right)^{2}-\left(0\,\frac{m}{s} \right)^{2}}{2\cdot \left(9.807\,\frac{m}{s^{2}} \right)}$

$y_{2} = 39.993\,m$

The ball will reach a maximum height of 39.993 meters.

Given the absence of non-conservative forces, the ball exhibits a free fall. The time needed for the ball to reach its maximum height is computed from the following kinematic formula:

$t = \frac{v_{2}-v_{1}}{-g}$ (4)