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2 years ago

What is the radius of the circle x2+y2=36? first to answer will mark brainiest

Mathematics

2 answers:

Katena32 [7]2 years ago

5 0

Answer:

Step-by-step explanation:

Sveta_85 [38]2 years ago

4 0

Answer:rtyuiop

Step-by-step explanation:

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One of the roots of the quadratic equation dx^2+cx+p=0 is twice the other, find the relationship between d, c and p

scZoUnD [109]

Answer:

$c^2 = 9dp$

Step-by-step explanation:

Given

$dx^2 + cx + p = 0$

Let the roots be $\alpha$ and $\beta$

So:

$\alpha = 2\beta$

Required

Determine the relationship between d, c and p

$dx^2 + cx + p = 0$

Divide through by d

$\frac{dx^2}{d} + \frac{cx}{d} + \frac{p}{d} = 0$

$x^2 + \frac{c}{d}x + \frac{p}{d} = 0$

A quadratic equation has the form:

$x^2 - (\alpha + \beta)x + \alpha \beta = 0$

So:

$x^2 - (2\beta+ \beta)x + \beta*\beta = 0$

$x^2 - (3\beta)x + \beta^2 = 0$

So, we have:

$\frac{c}{d} = -3\beta$ -- (1)

and

$\frac{p}{d} = \beta^2$ -- (2)

Make $\beta$ the subject in (1)

$\frac{c}{d} = -3\beta$

$\beta = -\frac{c}{3d}$

Substitute $\beta = -\frac{c}{3d}$ in (2)

$\frac{p}{d} = (-\frac{c}{3d})^2$

$\frac{p}{d} = \frac{c^2}{9d^2}$

Multiply both sides by d

$d * \frac{p}{d} = \frac{c^2}{9d^2}*d$

$p = \frac{c^2}{9d}$

Cross Multiply

$9dp = c^2$

$c^2 = 9dp$

Hence, the relationship between d, c and p is: $c^2 = 9dp$

8 0

2 years ago

Shaz is cleaning under the kitchen sink. He found five 2-liter bottles of glass cleaner. None of the bottles is full. The bottle

Stels [109]

Sbshehe fjshebd Shane

6 0

3 years ago

Read 2 more answers

Which of the following is most likely the next step in the series? Choices: 10A, 21b, 32C, 43d, 54E, 65f. . A.66g. B.76g. C.76G.

Katena32 [7]

First, we pay attention to the numerical coefficients of the terms in the series: 10, 21, 32, 43, 54, 65. Conclusively they form an arithmetic sequence with a common difference of 11. Thus, the next numerical coefficient is 76. Then, we pay attention to the letters which are just arrange alphabetically. The next letter ought to be G which needs to be capitalized. Thus, the answer is letter C. 76G.

3 0

2 years ago

Please help me for brainiest:(:(:(:(:(

Neko [114]

Answer:

15. 1/3 (33%)

16. 1/6 (16.66%)

17. 1/2 (50%)

18. 1/2 (50%)

19. 1/1 (100%)

20. 0/1 (0%)

Step-by-step explanation:

7 0

3 years ago

A point charge q1 = 3.30nC is located on the x-axis at x= 1.90m , and a second point charge q2= -6.40 nC is on the y-axis at y=

Dahasolnce [82]

Answer:

Step-by-step explanation:

charge q1 is placed at x = 1.90 m and the charge q2 is placed at y = 1.15 m

here, the charge enclosed in a sphere is zero as the radius of sphere is 0.625 m which is less than the x = 1.90 m and y = 1.15 m. So by the Gauss's theorem,

$\phi =\frac{q}{\epsilon _{0}}$

where q is the charge enclosed, as the charge enclosed is zero so the electric flux is zero.

3 0

2 years ago