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Soloha48 [4]
2 years ago
9

Investment question Part 2: $3,500 is invested at 7%. How much money

Mathematics
1 answer:
antiseptic1488 [7]2 years ago
4 0

Answer:

$7665

Explanation:

simple interest: principal * rate (%) * time (years)

<u>Given:</u>

principal: $3,500

rate: 7%

time: 17 years

<u>Solve for interest received:</u>

3,500 * 7% * 17

$4165

<u>Total money in account:</u>

$4165 + $3,500

$7665

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The length of a rectangular garden is 5 times its width.
Delvig [45]

Answer:

  • 10 m and 50 m

Step-by-step explanation:

<h3>Given</h3>
  • l = 5w
  • A = 500 m²
<h3>To find</h3>
  • Length and width
<h3>Solution</h3>

Area formula

  • A = lw
  • A= 5w*w= 5w²
  • 5w² = 500
  • w²= 100
  • w = √100
  • w = 10 m

Then

  • l = 5w = 5*10 m = 50 m

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2 years ago
Which set of reflections would carry rectangle ABCD onto itself?
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Answer:

i think that the answer would be but im not 100% sure

Step-by-step explanation:


5 0
3 years ago
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Please help with accounting. Use the following information to complete the partial worksheet for Bill’s Company. Record the appr
Ket [755]

If I am reading this right, it looks like the 10, 3, 2, 1 are Adjustments and the Adjusted TB should equal the difference. Make sure you know how to add and subtract the debit and credit adjustments correctly.

TB +/- Adj = ATB

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3 years ago
Im so lost, please help me asap
almond37 [142]

Answer:

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8 0
2 years ago
Select ALL the correct answers.
Marina CMI [18]

Answer:

The median of A is the same as the median of B.

The interquartile range of B is greater than the interquartile range of A.

Step-by-step explanation:

Given that:

A = number of runs allowed in first 9 games

A = {1, 4, 2, 2, 3, 1, 1, 2, 1}

Rearranging A : 1, 1, 1, 1, 2, 2, 2, 3, 4

Median A = 1/2(n + 1) th term

Median A = 1/2(10) = 5th term = 2

Q1 of A = 1/4(10) = 2.5th term = (1 + 1)/ 2 = 1

Q3 of A = 3/4(10) = 7.5th term = (2+3)/2 = 2.5

Interquartile range = Q3 - Q1 = 2.5 - 1 = 1.5

Number of runs allowed in 10th game = 9

B = {1, 4, 2, 2, 3, 1, 1, 2, 1, 9}

Rearranging B = 1, 1, 1, 1, 2, 2, 2, 3, 4, 9

Median A = 1/2(n + 1) th term

Median A = 1/2(11) = 5.5th term = (2+2)/2 = 2

Q1 of A = 1/4(11) = 2.75th tetm = (1 + 1)/ 2 = 1

Q3 of A = 3/4(11) = 8.25th term = (3+4)/2 = 3.5

Interquartile range = Q3 - Q1 = 3.5 - 1 = 2.5

Median A = 2 ; median B = 2

IQR B = 2.5 ; IQR A = 1.5 ; IQR B > IQR A

7 0
2 years ago
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