Identify the oxidation numbers for all the elements in the reactants and products for 2mno4−(aq)+3s2−(aq)+4h2o(l)→3s(s)+2mno2(s)
+8oh−(aq)
1 answer:
The oxidation number if eah of the elements is as follows;
- Oxidation number of Mn is + 7 on the right hand side and +4 on the right hand side
- Oxidation number if hydrogen is +1 on both sides
- The oxidation number of oxygen is -2 on both sides
- The oxidation number of sulfur is -2 on the lefthand side and zero on the right hand side.
<h3>What is a redox reaction?</h3>
A redox reaction is one in which there is a change in the oxidation number of the reactants from left to right.
Let us now consider the oxidation number of each element from left to right;
- Oxidation number of Mn is + 7 on the right hand side and +4 on the right hand side
- Oxidation number if hydrogen is +1 on both sides
- The oxidation number of oxygen is -2 on both sides
- The oxidation number of sulfur is -2 on the lefthand side and zero on the right hand side.
Learn more about oxidation number: brainly.com/question/15167411?
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